Example 5 - Chapter 13 Class 12 Probability
Last updated at May 29, 2018 by Teachoo
Transcript
Example 5 (Introduction) A die is thrown 3 times S = {(1,1,1), (1,1,2), .........., (1,1,6), (1,2,1), (1,2,2), .........., (1,2,6), (1,3,1), (1,3,2), .........., (1,3,6), (1,4,1), (1,4,2), .........., (1,4,6), (1,5,1), (1,5,2), .........., (1,5,6), (1,6,1), (1,6,2), .........., (1,6,6), (2,1,1), (2,1,2), .........., (2,1,6), (2,2,1), (2,2,2), .........., (2,2,6), (2,3,1), (2,3,2), .........., (2,3,6), (2,4,1), (2,4,2), .........., (2,4,6), (2,5,1), (2,5,2), .........., (2,5,6), (2,6,1), (2,6,2), .........., (2,6,6), (3,1,1), (3,1,2), .........., (3,1,6), (3,2,1),.........., (3,2,6), (3,3,1),.........., (3,3,6), (3,4,1),.........., (3,4,6), (3,5,1),.........., (3,5,6), (3,6,1),.........., (3,6,6), (4,1,1), ……………..(4,6,6), (5,1,1), ……………..(5,6,6), (6,1,1), ……………..(6,6,6), Example 5 A die is thrown three times. Events A and B are defined as below: A : 4 on the third throw B : 6 on the first and 5 on the second throw Find the probability of A given that B has already occurred. A die is thrown 3 times S = {(1,1,1),.........., (1,6,6), (2,1,1), .........., (2,6,6), (3,1,1), .........., (3,6,6), (4,1,1), ……………..(4,6,6), (5,1,1), ……………..(5,6,6), (6,1,1), ……………..(6,6,6), Given, A : 4 on the third throw B : 6 on the first & 5 on the second throw A ∩ B = {(6,5,4)} So, P(A ∩ B) = 1216 We need to find the probability of A, given that B has already occurred i.e. P(A|B) Now, P(A|B) = 𝑃(𝐴 ∩ 𝐵)𝑃(𝐵) = 1216 6216 = 16 ∴ P(A|B) = 𝟏𝟔
Examples
Example 1
Example 2
Example 3
Example 4
Example 5 You are here
Example 6 Important
Example 7 Important
Example 8
Example 9
Example 10
Example 11 Important
Example 12
Example 13
Example 14
Example 15
Example 16
Example 17 Important
Example 18 Important
Example 19
Example 20 Important
Example 21 Important
Example 22
Example 23
Example 24
Example 25 Important
Example 26 Important
Example 27 Important
Example 28 Important
Example 29 Important
Example 30
Example 31 Important
Example 32 Important
Example 33
Example 34
Example 35 Important
Example 36 Important
Example 37
Chapter 13 Class 12 Probability
Serial order wise
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.