# Example 9 - Chapter 13 Class 12 Probability (Term 2)

Last updated at Dec. 3, 2020 by Teachoo

Examples

Example 1

Example 2

Example 3

Example 4

Example 5 Important

Example 6

Example 7 Important

Example 8

Example 9 Important You are here

Example 10

Example 11 Important

Example 12 Important

Example 13 Important

Example 14 Important

Example 15 Important

Example 16

Example 17 Important

Example 18 Important

Example 19 Important

Example 20 Important

Example 21 Important

Example 22

Example 23

Example 24 Important

Example 25 Important

Example 26 Important

Example 27 Deleted for CBSE Board 2022 Exams

Example 28 Important Deleted for CBSE Board 2022 Exams

Example 29 Important Deleted for CBSE Board 2022 Exams

Example 30 Important Deleted for CBSE Board 2022 Exams

Example 31 Important Deleted for CBSE Board 2022 Exams

Example 32 Important Deleted for CBSE Board 2022 Exams

Example 33 Important

Example 34 Deleted for CBSE Board 2022 Exams

Example 35 Deleted for CBSE Board 2022 Exams

Example 36 Important

Example 37 Important

Chapter 13 Class 12 Probability (Term 2)

Serial order wise

Last updated at Dec. 3, 2020 by Teachoo

Hello! Teachoo has made these pages with hours (even days!) of effort and love. Your Board exams are coming, if Teachoo has been of any help in the whole year of studying... please consider making a donation to support us.

Hello! Teachoo has made these pages with hours (even days!) of effort and love. Your Board exams are coming, if Teachoo has been of any help in the whole year of studying... please consider making a donation to support us.

Example 9 Three cards are drawn successively, without replacement from a pack of 52 well shuffled cards. What is the probability that first two cards are kings and the third card drawn is an ace? Probability first two cards are king & third drawn is ace = Probability first card is king × Probability second card is king , if first card is king × Probability third card is ace, if first two are kings Finding Probabilities separately Probability first card is king Number of kings in a pack of 52 cards = 4 So, Probability = (𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑘𝑖𝑛𝑔𝑠)/(𝑇𝑜𝑡𝑎𝑙 𝑛𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑐𝑎𝑟𝑑𝑠) = (4 )/52 = 1/13 Probability that the second card drawn is king, if the first card drawn has a king If first card drawn has king, Total number of kings left in the pack = 3 & Total number of cards in the pack = 51 So, Probability = 3/51 = 1/17 Probability that the third card is an ace, given first two cards were kings If first two card drawn were kings, Total number of aces left in the pack = 4 & Total number of cards in the pack = 50 So, Probability = 4/50 = 2/25 Therefore, Probability first two cards are king & third drawn is ace = Probability first card is king × Probability second card is king , if first card is king × Probability third card is ace, if first two are kings = 𝟏/𝟏𝟑 × 𝟏/𝟏𝟕 × 𝟐/𝟐𝟓 = 𝟐/𝟓𝟓𝟐𝟓