# Example 7

Last updated at March 11, 2017 by Teachoo

Last updated at March 11, 2017 by Teachoo

Transcript

Example 7 Consider the experiment of tossing a coin. If the coin shows head, toss it again but if it shows tail, then throw a die. Find the conditional probability of the event that ‘the die shows a number greater than 4’ given that ‘there is at least one tail’. A coin is tossed. if the coin shows head, it is tossed again. If it shows tail, then a die is thrown. Hence different value of probabilities are We need to find the probability that the die shows a number greater than 4, given that there is at least one tail. Now, F : Number greater than 4 on the die E : at least one tail We need to find P(E|F) Also, E ∩ F = {(T, 5), (T, 6)} So, P(E ∩ F) = P(T, 5) + P(T, 6) So, P(E ∩ F) = P(T, 5) + P(T, 6) = 112 + 112 = 212 = 16 Now, P(E|F) = 𝑃(𝐸 ∩ 𝐹)𝑃(𝐹) = 16 34 = 16 × 43 = 𝟐𝟗 Therefore, required probability is 29

Example 1

Example 2

Example 3

Example 4

Example 5

Example 6 Important

Example 7 Important You are here

Example 8

Example 9

Example 10

Example 11 Important

Example 12

Example 13

Example 14

Example 15

Example 16

Example 17 Important

Example 18 Important

Example 19

Example 20 Important

Example 21 Important

Example 22

Example 23

Example 24

Example 25 Important

Example 26 Important

Example 27 Important

Example 28 Important

Example 29 Important

Example 30

Example 31 Important

Example 32 Important

Example 33

Example 34

Example 35 Important

Example 36 Important

Example 37

Chapter 13 Class 12 Probability

Serial order wise

About the Author

CA Maninder Singh

CA Maninder Singh is a Chartered Accountant for the past 8 years. He provides courses for Practical Accounts, Taxation and Efiling at teachoo.com .