Subscribe to our Youtube Channel - https://you.tube/teachoo
Example 32 - Chapter 13 Class 12 Probability
Last updated at Feb. 15, 2020 by Teachoo
Transcript
Example 32 Ten eggs are drawn successively with replacement from a lot containing 10% defective eggs. Find the probability that there is atleast one defective egg.Let X : be the number of defective eggs Picking eggs with replacement is a Bernoulli trial So, X has binomial distribution P(X = x) = nCx ๐^(๐โ๐) ๐^๐ Here, n = number of eggs picked = 10 p = Probability of getting defective egg = 10% = 10/100 = 1/10 q = 1 โ p = 1 โ 1/10 = 9/10 Hence, P(X = x) = 10Cx (๐/๐๐)^๐ (๐/๐๐)^(๐๐ โ ๐) We need to find Probability that there is atleast one defective egg P(atleast one defective egg) = 1 โ P(getting 0 defective eggs) = 1 โ P(X = 0) = 1 โ 10C0(1/10)^0 (9/10)^(10 โ0) = 1 โ 1 ร 1 ร (9/10)^10 = 1 โ (9/10)^10
Examples
Example 1
Example 2
Example 3
Example 4
Example 5 Important
Example 6
Example 7 Important
Example 8
Example 9 Important
Example 10
Example 11 Important
Example 12 Important
Example 13 Important
Example 14 Important
Example 15 Important
Example 16
Example 17 Important
Example 18 Important
Example 19 Important
Example 20 Important
Example 21 Important
Example 22
Example 23
Example 24 Important
Example 25 Important
Example 26 Important
Example 27 Not in Syllabus - CBSE Exams 2021
Example 28 Important Not in Syllabus - CBSE Exams 2021
Example 29 Important Not in Syllabus - CBSE Exams 2021
Example 30 Important Not in Syllabus - CBSE Exams 2021
Example 31 Important Not in Syllabus - CBSE Exams 2021
Example 32 Important Not in Syllabus - CBSE Exams 2021 You are here
Example 33 Important
Example 34 Important Not in Syllabus - CBSE Exams 2021
Example 35 Important
Example 36 Important
Example 37 Important
Chapter 13 Class 12 Probability
Serial order wise
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.