Example 32 - Chapter 13 Class 12 Probability (Term 2)
Last updated at Feb. 15, 2020 by Teachoo
Transcript
Example 32 Ten eggs are drawn successively with replacement from a lot containing 10% defective eggs. Find the probability that there is atleast one defective egg.Let X : be the number of defective eggs Picking eggs with replacement is a Bernoulli trial So, X has binomial distribution P(X = x) = nCx ๐^(๐โ๐) ๐^๐ Here, n = number of eggs picked = 10 p = Probability of getting defective egg = 10% = 10/100 = 1/10 q = 1 โ p = 1 โ 1/10 = 9/10 Hence, P(X = x) = 10Cx (๐/๐๐)^๐ (๐/๐๐)^(๐๐ โ ๐) We need to find Probability that there is atleast one defective egg P(atleast one defective egg) = 1 โ P(getting 0 defective eggs) = 1 โ P(X = 0) = 1 โ 10C0(1/10)^0 (9/10)^(10 โ0) = 1 โ 1 ร 1 ร (9/10)^10 = 1 โ (9/10)^10
Examples
Example 1
Example 2
Example 3
Example 4
Example 5 Important
Example 6
Example 7 Important
Example 8
Example 9 Important
Example 10
Example 11 Important
Example 12 Important
Example 13 Important
Example 14 Important
Example 15 Important
Example 16
Example 17 Important
Example 18 Important
Example 19 Important
Example 20 Important
Example 21 Important
Example 22
Example 23
Example 24 Important
Example 25 Important
Example 26 Important
Example 27 Deleted for CBSE Board 2022 Exams
Example 28 Important Deleted for CBSE Board 2022 Exams
Example 29 Important Deleted for CBSE Board 2022 Exams
Example 30 Important Deleted for CBSE Board 2022 Exams
Example 31 Important Deleted for CBSE Board 2022 Exams
Example 32 Important Deleted for CBSE Board 2022 Exams You are here
Example 33 Important
Example 34 Important Deleted for CBSE Board 2022 Exams
Example 35 Important Deleted for CBSE Board 2022 Exams
Example 36 Important
Example 37 Important
Chapter 13 Class 12 Probability (Term 2)
Serial order wise
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.