Example 32 - Chapter 13 Class 12 Probability
Last updated at May 29, 2018 by Teachoo
Transcript
Example 32 Ten eggs are drawn successively with replacement from a lot containing 10% defective eggs. Find the probability that there is atleast one defective egg. Let X : be the number of defective eggs Picking eggs with replacement is a Bernoulli trial So, X has binomial distribution P(X = x) = nCx n = number of eggs picked = 10 p = Probability of getting defective egg = 10% = 10 100 = 1 10 q = 1 p = 1 1 10 = 9 10 Hence, P(X = x) = 10Cx We need to find Probability that there is atleast one defective egg P(atleast one defective egg) = 1 P(getting 0 defective eggs) = 1 P(X = 0) = 1 10C0 1 10 0 9 10 10 0 = 1 1 1 9 10 10 = 1 9 10 10
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Chapter 13 Class 12 Probability
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About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.