Example 32
Last updated at March 11, 2017 by Teachoo
Transcript
Example 32 Ten eggs are drawn successively with replacement from a lot containing 10% defective eggs. Find the probability that there is atleast one defective egg. Let X : be the number of defective eggs Picking eggs with replacement is a Bernoulli trial So, X has binomial distribution P(X = x) = nCx 𝒒𝒏−𝒙 𝒑𝒙 n = number of eggs picked = 10 p = Probability of getting defective egg = 10% = 10100 = 110 q = 1 – p = 1 – 110 = 910 Hence, P(X = x) = 10Cx 𝟏𝟏𝟎𝒙 𝟗𝟏𝟎𝟏𝟎 − 𝒙 We need to find Probability that there is atleast one defective egg P(atleast one defective egg) = 1 – P(getting 0 defective eggs) = 1 – P(X = 0) = 1 – 10C0 1100 91010 −0 = 1 – 1 × 1 × 91010 = 1 – 91010
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Chapter 13 Class 12 Probability
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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 7 years. He provides courses for Mathematics and Science from Class 6 to 12. You can learn personally from here https://www.teachoo.com/premium/maths-and-science-classes/.