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  1. Chapter 13 Class 12 Probability
  2. Serial order wise

Transcript

Example 32 Ten eggs are drawn successively with replacement from a lot containing 10% defective eggs. Find the probability that there is atleast one defective egg.Let X : be the number of defective eggs Picking eggs with replacement is a Bernoulli trial So, X has binomial distribution P(X = x) = nCx ๐’’^(๐’โˆ’๐’™) ๐’‘^๐’™ Here, n = number of eggs picked = 10 p = Probability of getting defective egg = 10% = 10/100 = 1/10 q = 1 โ€“ p = 1 โ€“ 1/10 = 9/10 Hence, P(X = x) = 10Cx (๐Ÿ/๐Ÿ๐ŸŽ)^๐’™ (๐Ÿ—/๐Ÿ๐ŸŽ)^(๐Ÿ๐ŸŽ โˆ’ ๐’™) We need to find Probability that there is atleast one defective egg P(atleast one defective egg) = 1 โ€“ P(getting 0 defective eggs) = 1 โ€“ P(X = 0) = 1 โ€“ 10C0(1/10)^0 (9/10)^(10 โˆ’0) = 1 โ€“ 1 ร— 1 ร— (9/10)^10 = 1 โ€“ (9/10)^10

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.