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Example 32 - Chapter 13 Class 12 Probability
Last updated at Feb. 15, 2020 by Teachoo
Transcript
Example 32 Ten eggs are drawn successively with replacement from a lot containing 10% defective eggs. Find the probability that there is atleast one defective egg.Let X : be the number of defective eggs Picking eggs with replacement is a Bernoulli trial So, X has binomial distribution P(X = x) = nCx ๐^(๐โ๐) ๐^๐ Here, n = number of eggs picked = 10 p = Probability of getting defective egg = 10% = 10/100 = 1/10 q = 1 โ p = 1 โ 1/10 = 9/10 Hence, P(X = x) = 10Cx (๐/๐๐)^๐ (๐/๐๐)^(๐๐ โ ๐) We need to find Probability that there is atleast one defective egg P(atleast one defective egg) = 1 โ P(getting 0 defective eggs) = 1 โ P(X = 0) = 1 โ 10C0(1/10)^0 (9/10)^(10 โ0) = 1 โ 1 ร 1 ร (9/10)^10 = 1 โ (9/10)^10
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Chapter 13 Class 12 Probability
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About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.