# Example 32 - Chapter 13 Class 12 Probability

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Example 32 Ten eggs are drawn successively with replacement from a lot containing 10% defective eggs. Find the probability that there is atleast one defective egg. Let X : be the number of defective eggs Picking eggs with replacement is a Bernoulli trial So, X has binomial distribution P(X = x) = nCx n = number of eggs picked = 10 p = Probability of getting defective egg = 10% = 10 100 = 1 10 q = 1 p = 1 1 10 = 9 10 Hence, P(X = x) = 10Cx We need to find Probability that there is atleast one defective egg P(atleast one defective egg) = 1 P(getting 0 defective eggs) = 1 P(X = 0) = 1 10C0 1 10 0 9 10 10 0 = 1 1 1 9 10 10 = 1 9 10 10

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Chapter 13 Class 12 Probability

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.