Example 28 - Chapter 13 Class 12 Probability
Last updated at May 29, 2018 by Teachoo
Transcript
Example 28 Find the variance of the number obtained on a throw of an unbiased die. Let X be number obtained on a throw So, value of X can be 1, 2, 3, 4, 5 or 6 Since die unbiased, Probability of getting of each number is equal P(X = 1) = P(X = 2) = P(X = 3) = P(X = 4) = P(X = 5) = P(X = 6) = 1 6 Hence, probability distribution The mean Expectation value is given by E(X) = = = 1 1 6 +2 1 6 + 3 1 6 + 3 1 6 + 5 1 6 + 6 1 6 = 21 6 The variance of x is given by : Var = So, finding 2 E 2 = = 1 2 = 12 1 6 +22 1 6 + 32 1 6 + 42 1 6 + 52 1 6 + 62 1 6 = 1 + 4 + 9 + 16 + 25 + 36 6 = 91 6 Now, Var = 2 2 = 91 6 21 6 2 = 91 6 441 36 = 546 441 36 = 105 36 = 35 12 Hence, variance is
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Chapter 13 Class 12 Probability
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.