Solve all your doubts with Teachoo Black (new monthly pack available now!)
Example 16 - Chapter 13 Class 12 Probability (Term 2)
Last updated at May 29, 2018 by Teachoo
Examples
Example 1
Example 2
Example 3
Example 4
Example 5 Important
Example 6
Example 7 Important
Example 8
Example 9 Important
Example 10
Example 11 Important
Example 12 Important
Example 13 Important
Example 14 Important
Example 15 Important
Example 16 You are here
Example 17 Important
Example 18 Important
Example 19 Important
Example 20 Important
Example 21 Important
Example 22
Example 23
Example 24 Important
Example 25 Important
Example 26 Important
Example 27
Example 28 Important Deleted for CBSE Board 2023 Exams
Example 29 Important
Example 30 Important Deleted for CBSE Board 2023 Exams
Example 31 Important Deleted for CBSE Board 2023 Exams
Example 32 Important Deleted for CBSE Board 2023 Exams
Example 33 Important
Example 34 Deleted for CBSE Board 2023 Exams
Example 35
Example 36 Important
Example 37 Important
Chapter 13 Class 12 Probability
Serial order wise
Transcript
Example 16 Bag I contains 3 red and 4 black balls while another Bag II contains 5 red and 6 black balls. One ball is drawn at random from one of the bags and it is found to be red. Find the probability that it was drawn from Bag II. Let E1 : Bag selected is bag 1 E2 : Bag selected is bag 2 A : Ball selected is Red B : Ball selected is Black We need to find P(ball was drawn from bag 2, if ball is red) = P(E2|A) We need to find, 𝑃 𝐸2|𝐴= 𝑃 𝐴 𝑃(𝐴|𝐸2)𝑃 𝐸1 𝑃 𝐴|𝐸1 + 𝑃 𝐸2 𝑃(𝐴|𝐸2) Putting values in formula, P(E2|A) = 12 × 511 12 × 37 + 12 × 511 = 12 × 511 12 [ 37 × 511 ] = 511 33 + 3577 = 511 6877 = 511 × 7768 = 3568 Therefore, required probability is 𝟑𝟓𝟔𝟖
