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  1. Chapter 13 Class 12 Probability
  2. Serial order wise

Transcript

Example 34 Find the mean of the Binomial distribution B(4, 1/3) B(4, 1/3) means Here, n = 4, p = 1/3 So, q = 1 โˆ’ 1/3 = 2/3 Hence, P (X = x) = 4Cx (๐Ÿ/๐Ÿ‘)^๐’™ (๐Ÿ/๐Ÿ‘)^(๐Ÿ’โˆ’๐’™) Mean of distribution = P (X = x) = 4Cx (1/3)^๐‘ฅ (2/3)^(4โˆ’๐‘ฅ) Mean = = 0 + 1 ร— 4C1 (1/3)^1 (2/3)^3+ 2 ร— 4C2 (1/3)^2 (2/3)^2 + 3 ร— 4C3 (1/3)^3 (2/3) + 4 ร— 4C4 (1/3)^4 (2/3)^0 = 4 ร— 1/3 ร— 8/27 + 2 ร— 6 ร— 1/9 ร— 4/9 + 3 ร— 4 ร— 1/27 ร— 2/3 + 4 ร— 1/3^4 ร— 1 = 32/81+48/81+24/81+4/81 = 108/81 = ๐Ÿ’/๐Ÿ‘

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.