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Example 34 - Find mean of Binomial distribution B(4, 1/3)

Example 34 - Chapter 13 Class 12 Probability - Part 2
Example 34 - Chapter 13 Class 12 Probability - Part 3

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Transcript

Example 34 Find the mean of the Binomial distribution B(4, 1/3) B(4, 1/3) means Here, n = 4, p = 1/3 So, q = 1 βˆ’ 1/3 = 2/3 Hence, P (X = x) = 4Cx (𝟏/πŸ‘)^𝒙 (𝟐/πŸ‘)^(πŸ’βˆ’π’™) Mean of distribution = P (X = x) = 4Cx (1/3)^π‘₯ (2/3)^(4βˆ’π‘₯) Mean = = 0 + 1 Γ— 4C1 (1/3)^1 (2/3)^3+ 2 Γ— 4C2 (1/3)^2 (2/3)^2 + 3 Γ— 4C3 (1/3)^3 (2/3) + 4 Γ— 4C4 (1/3)^4 (2/3)^0 = 4 Γ— 1/3 Γ— 8/27 + 2 Γ— 6 Γ— 1/9 Γ— 4/9 + 3 Γ— 4 Γ— 1/27 Γ— 2/3 + 4 Γ— 1/3^4 Γ— 1 = 32/81+48/81+24/81+4/81 = 108/81 = πŸ’/πŸ‘

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.