Example 17 - Chapter 13 Class 12 Probability
Last updated at May 29, 2018 by Teachoo
Transcript
Example 17 Given three identical boxes I, II and III, each containing two coins. In box I, both coins are gold coins, in box II, both are silver coins and in the box III, there is one gold and one silver coin. A person chooses a box at random and takes out a coin. If the coin is of gold, what is the probability that the other coin in the box is also of gold? Let B1 : Selecting Box 1 having two gold coins B2 : Selecting Box 2 having two silver coins B3 : Selecting Box 3 having one gold and one silver coin G : The second coin is of gold We need to find the Probability that the other coin in the box is also of gold, if the first coin is of gold i.e. P(B1|G) P(B1|G) = 𝑃 𝐵1.𝑃(𝐺| 𝐵1)𝑃 𝐵1.𝑃(𝐺| 𝐵1)+𝑃 𝐵2.𝑃(𝐺| 𝐵2)+𝑃 𝐵3.𝑃(𝐺| 𝐵3) Putting values in formula, 𝑃 B1|𝐺 = 13 × 1 13 × 1 + 13 × 0 + 13 × 12 = 13 × 1 13 × 1 + 0 + 12 = 1 1 + 12 = 1 32 = 𝟐𝟑 Therefore, required probability is 23
Examples
Example 1
Example 2
Example 3
Example 4
Example 5
Example 6 Important
Example 7 Important
Example 8
Example 9
Example 10
Example 11 Important
Example 12
Example 13
Example 14
Example 15
Example 16
Example 17 Important You are here
Example 18 Important
Example 19
Example 20 Important
Example 21 Important
Example 22
Example 23
Example 24
Example 25 Important
Example 26 Important
Example 27 Important
Example 28 Important
Example 29 Important
Example 30
Example 31 Important
Example 32 Important
Example 33
Example 34
Example 35 Important
Example 36 Important
Example 37
Chapter 13 Class 12 Probability
Serial order wise
About the Author
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.