# Example 17 - Chapter 13 Class 12 Probability

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Example 17 Given three identical boxes I, II and III, each containing two coins. In box I, both coins are gold coins, in box II, both are silver coins and in the box III, there is one gold and one silver coin. A person chooses a box at random and takes out a coin. If the coin is of gold, what is the probability that the other coin in the box is also of gold? Let B1 : Selecting Box 1 having two gold coins B2 : Selecting Box 2 having two silver coins B3 : Selecting Box 3 having one gold and one silver coin G : The second coin is of gold We need to find the Probability that the other coin in the box is also of gold, if the first coin is of gold i.e. P(B1|G) P(B1|G) = 𝑃 𝐵1.𝑃(𝐺| 𝐵1)𝑃 𝐵1.𝑃(𝐺| 𝐵1)+𝑃 𝐵2.𝑃(𝐺| 𝐵2)+𝑃 𝐵3.𝑃(𝐺| 𝐵3) Putting values in formula, 𝑃 B1|𝐺 = 13 × 1 13 × 1 + 13 × 0 + 13 × 12 = 13 × 1 13 × 1 + 0 + 12 = 1 1 + 12 = 1 32 = 𝟐𝟑 Therefore, required probability is 23

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Chapter 13 Class 12 Probability

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.