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Example 17 - Given three identical boxes I, II, III, two coins - Bayes theoram

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  1. Chapter 13 Class 12 Probability
  2. Serial order wise
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Example 17 Given three identical boxes I, II and III, each containing two coins. In box I, both coins are gold coins, in box II, both are silver coins and in the box III, there is one gold and one silver coin. A person chooses a box at random and takes out a coin. If the coin is of gold, what is the probability that the other coin in the box is also of gold? Let B1 : Selecting Box 1 having two gold coins B2 : Selecting Box 2 having two silver coins B3 : Selecting Box 3 having one gold and one silver coin G : The second coin is of gold We need to find the Probability that the other coin in the box is also of gold, if the first coin is of gold i.e. P(B1|G) P(B1|G) = 𝑃 𝐵﷮1﷯﷯.𝑃(𝐺| 𝐵﷮1﷯)﷮𝑃 𝐵﷮1﷯﷯.𝑃(𝐺| 𝐵﷮1﷯)+𝑃 𝐵﷮2﷯﷯.𝑃(𝐺| 𝐵﷮2﷯)+𝑃 𝐵﷮3﷯﷯.𝑃(𝐺| 𝐵﷮3﷯)﷯ Putting values in formula, 𝑃 B1|𝐺﷯ = 1﷮3﷯ × 1﷮ 1﷮3﷯ × 1 + 1﷮3﷯ × 0 + 1﷮3﷯ × 1﷮2﷯ ﷯ = 1﷮3﷯ × 1﷮ 1﷮3﷯ × 1 + 0 + 1﷮2﷯﷯ ﷯ = 1﷮ 1 + 1﷮2﷯ ﷯ = 1﷮ 3﷮2﷯ ﷯ = 𝟐﷮𝟑﷯ Therefore, required probability is 2﷮3﷯

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