Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class

Examples

Example 1

Example 2

Example 3

Example 4

Example 5 Important

Example 6

Example 7 Important

Example 8

Example 9 Important

Example 10

Example 11 Important

Example 12 Important

Example 13 Important

Example 14 Important

Example 15 Important

Example 16

Example 17 Important You are here

Example 18 Important

Example 19 Important

Example 20 Important

Example 21 Important

Example 22 Important

Example 23 Important

Example 24 Important

Question 1 Deleted for CBSE Board 2024 Exams

Question 2 Deleted for CBSE Board 2024 Exams

Question 3 Important Deleted for CBSE Board 2024 Exams

Question 4 Important Deleted for CBSE Board 2024 Exams

Question 5 Important Deleted for CBSE Board 2024 Exams

Question 6 Deleted for CBSE Board 2024 Exams

Question 7 Important Deleted for CBSE Board 2024 Exams

Question 8 Important Deleted for CBSE Board 2024 Exams

Question 9 Important Deleted for CBSE Board 2024 Exams

Question 10 Important Deleted for CBSE Board 2024 Exams

Question 11 Important Deleted for CBSE Board 2024 Exams

Question 12 Deleted for CBSE Board 2024 Exams

Question 13 Deleted for CBSE Board 2024 Exams

Chapter 13 Class 12 Probability

Serial order wise

Last updated at Aug. 16, 2023 by Teachoo

Example 17 Given three identical boxes I, II and III, each containing two coins. In box I, both coins are gold coins, in box II, both are silver coins and in the box III, there is one gold and one silver coin. A person chooses a box at coin. If the coin is of gold, what is the probability that the other coin in the box is also of gold?Let B1 : Selecting Box 1 having two gold coins B2 : Selecting Box 2 having two silver coins B3 : Selecting Box 3 having one gold and one silver coin G : The second coin is of gold We need to find the Probability that the other coin in the box is also of gold, if the first coin is of gold i.e. P(B1"|"G) P(B1"|"G) = (𝑃(𝐵_1 ).𝑃(𝐺|𝐵_1))/(𝑃(𝐵_1 ).𝑃(𝐺|𝐵_1)+𝑃(𝐵_2 ).𝑃(𝐺|𝐵_2)+𝑃(𝐵_3 ).𝑃(𝐺|𝐵_3)) "P(B1)" = Probability of selecting Box 1 = 𝟏/𝟑 𝑷(𝑮"|B1") = Probability that second coin is of gold in Box 1 = 𝟏 "P(B2)" = Probability of selecting Box 2 = 𝟏/𝟑 𝑷(𝑮"|B2") = Probability that second coin is of gold in Box 2 = 𝟎 "P(B3)" = Probability of selecting Box 3 = 𝟏/𝟑 𝑷(𝑮"|B3") = Probability that second coin is of gold in Box 3 = 𝟏/𝟐 Putting values in formula, 𝑃("B1|" 𝐺) = (𝟏/𝟑 × 𝟏)/( 𝟏/𝟑 × 𝟏 + 𝟏/𝟑 × 𝟎 + 𝟏/𝟑 × 𝟏/𝟐 ) = (1/3 × 1)/( 1/3 × [1 + 0 + 1/2] ) = 1/( 1 + 1/2 ) = 1/( 3/2 ) = 𝟐/𝟑 Therefore, required probability is 2/3