Ex 5.5
Last updated at August 11, 2026 by Teachoo
Transcript
Ex 5.5, 15 Find ๐๐ฆ/๐๐ฅ of the functions in, ๐ฅ๐ฆ= ๐^((๐ฅ โ๐ฆ))Given ๐ฅ๐ฆ= ๐^((๐ฅ โ๐ฆ)) Taking log both sides log (๐ฅ๐ฆ) = log ๐^((๐ฅ โ๐ฆ)) log (๐ฅ๐ฆ) = (๐ฅ โ๐ฆ) log ๐ log ๐ฅ+logโก๐ฆ = (๐ฅ โ๐ฆ) (1) log ๐ฅ+logโก๐ฆ = (๐ฅ โ๐ฆ) (As ๐๐๐โก(๐^๐ )=๐ . ๐๐๐โก๐) Differentiating both sides ๐ค.๐.๐ก.๐ฅ. ๐(log ๐ฅ + logโก๐ฆ )/๐๐ฅ = (๐(๐ฅ โ ๐ฆ))/๐๐ฅ ๐(log ๐ฅ)/๐๐ฅ + ๐(logโก๐ฆ )/๐๐ฅ = ๐(๐ฅ)/๐๐ฅ โ ๐(๐ฆ)/๐๐ฅ 1/๐ฅ + ๐(logโก๐ฆ )/๐๐ฅ . ๐๐ฆ/๐๐ฆ = 1 โ ๐๐ฆ/๐๐ฅ 1/๐ฅ + ๐(logโก๐ฆ )/๐๐ฆ . ๐๐ฆ/๐๐ฅ = 1 โ ๐๐ฆ/๐๐ฅ 1/๐ฅ + 1/๐ฆ . ๐๐ฆ/๐๐ฅ = 1 โ ๐๐ฆ/๐๐ฅ 1/๐ฆ . ๐๐ฆ/๐๐ฅ + ๐๐ฆ/๐๐ฅ = 1 โ 1/๐ฅ ๐๐ฆ/๐๐ฅ (1/๐ฆ +1) = ("1 โ " 1/๐ฅ) ๐๐ฆ/๐๐ฅ ((1 + ๐ฆ)/๐ฆ) = ((๐ฅ โ 1)/๐ฅ) ๐๐ฆ/๐๐ฅ = ((๐ฅ โ 1)/๐ฆ) . (๐ฆ/(1 + ๐ฆ)) ๐ ๐/๐ ๐ = ๐(๐ โ ๐)/๐(๐ + ๐)