# Ex 5.5, 8

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Ex 5.5, 8 Differentiate the functions in, ( sin ) + sin 1 Let = sin + sin 1 Let = sin & = sin 1 = + Differentiating both sides . . . . = ( + ) = + Calculating = sin Taking log both sides log = log sin log = . log sin Differentiating both sides . . . . ( log ) = . log sin log . = . log sin log . = . log sin 1 . = . log sin 1 . = . log sin + log sin 1 . = 1 . log sin + 1 sin . sin 1 . = log sin + 1 sin . cos 1 . = log sin + cos sin = u log sin + cot = sin log sin + cot Calculating = sin 1 Differentiating both sides . . . . = sin 1 = 1 1 2 . = 1 1 . 1 2 = 1 2 1 = 1 2 1 = 1 2 2 Now , = + Putting value of & = + +

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.