CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard

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Question 38 (ii) (Choice 1) - CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at June 23, 2025 by

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Transcript

Distance travelled by bird is AD Now, AD = BE = CE – CB = CE βˆ’ 80 ∴ We need to find CE In right angle triangle DEC tan C = (𝑆𝑖𝑑𝑒 π‘œπ‘π‘π‘œπ‘ π‘–π‘‘π‘’ π‘‘π‘œ π‘Žπ‘›π‘”π‘™π‘’" " 𝐢)/(𝑆𝑖𝑑𝑒 π‘Žπ‘‘π‘—π‘Žπ‘π‘’π‘›π‘‘ π‘‘π‘œ π‘Žπ‘›π‘”π‘™π‘’" " 𝐢) tan C = (" " 𝐷𝐸)/𝐢𝐸 tan 30Β° = πŸ–πŸŽ/π‘ͺ𝑬 1/√3 = 80/𝐢𝐸 CE = 80βˆšπŸ‘ m Thus, AD = CE – CB = 80 √3 βˆ’ 80 = 80(βˆšπŸ‘ βˆ’ 1) m

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