If tan (A+B)=√3 and tan (A-B)=1/√3;0^∘<A+B<90^∘  ;A>B, find A and B.

This question is exactly same as Question 3 , Ex 8.2– NCERT BOOK

Please check the answer here https://www.teachoo.com/1772/530/Ex-8.2--3---If-tan-(A---B)--root-3-and-tan-(A---B)-/category/Ex-8.2/

If tan (A + B) = √3 and tan (A – B) = 1/√3 ; 0° < A + B < 90°; A > B, - CBSE Class 10 Sample Paper for 2024 Boards - Maths Standard

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo