Question 8 (iii) - Algebra Identities and Formulas - Chapter 8 Class 8 Algebraic Expressions and Identities

Last updated at August 14, 2026 by

Ex 9.5, 8 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 3

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Question 8 Using (𝑥+𝑎)(𝑥+𝑏)=𝑥^2+(𝑎+𝑏)𝑥+𝑎𝑏 , find (iii) 103 × 98 103 ×98 = (100+3)×(100−2) = (100+3)×[100+(−2)] (𝑥+𝑎)(𝑥+𝑏)=𝑥^2+(𝑎+𝑏)𝑥+𝑎𝑏 Putting 𝑥 = 100 , 𝑎 = 3 & 𝑏 = −2 = (100)^2+(3+2)(100)+(3)(−2) = 10000+100−6 = 10000+94 = 𝟏𝟎𝟎𝟗𝟒

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