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Ex 9.5, 7 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 3

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Ex 9.5, 7 Using π‘Ž^2βˆ’π‘^2=(π‘Ž+𝑏)(π‘Žβˆ’π‘) , find (iii) γ€–153γ€—^2βˆ’γ€–147γ€—^2 γ€–153γ€—^2βˆ’γ€–147γ€—^2 π‘Ž^2βˆ’π‘^2=(π‘Ž+𝑏)(π‘Žβˆ’π‘) Putting π‘Ž = 153 & 𝑏 = 147 π‘Ž^2βˆ’π‘^2=(π‘Ž+𝑏)(π‘Žβˆ’π‘) Putting π‘Ž = 153 & 𝑏 = 147

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