Ex 9.5, 8 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 4

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Ex 9.5, 8 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 5

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  1. Chapter 9 Class 8 Algebraic Expressions and Identities
  2. Serial order wise

Transcript

Ex 9.5, 8 Using (π‘₯+π‘Ž)(π‘₯+𝑏)=π‘₯^2+(π‘Ž+𝑏)π‘₯+π‘Žπ‘ , find (iv) 9.7 Γ— 9.8 9.7 Γ—9.8 = (10βˆ’0.3)Γ—(10βˆ’0.2) = (10+(βˆ’0.3))Γ—[10+(βˆ’0.2)] (π‘₯+π‘Ž)(π‘₯+𝑏)=π‘₯^2+(π‘Ž+𝑏)π‘₯+π‘Žπ‘ Putting π‘₯ = 10 , π‘Ž = βˆ’0.3 & 𝑏 = βˆ’0.2 = (10)^2+(βˆ’0.3βˆ’0.2)(10)+(βˆ’0.3)(βˆ’0.2) = 100+(βˆ’0.5Γ—10)+(0.3Γ—0.2) = 100βˆ’(5/10Γ—10)+(3/10Γ—2/10) = 100βˆ’5+6/100 = 95+0.06 = πŸ—πŸ“.πŸŽπŸ”

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