Get live Maths 1-on-1 Classs - Class 6 to 12
Ex 9.5, 8 (iv) - Chapter 9 Class 8 Algebraic Expressions and Identities
Last updated at March 22, 2023 by Teachoo
Ex 9.5
Ex 9.5, 1 (i)
Ex 9.5, 1 (ii) Important
Ex 9.5, 1 (iii)
Ex 9.5, 1 (iv)
Ex 9.5, 1 (v) Important
Ex 9.5, 1 (vi) Important
Ex 9.5, 1 (vii)
Ex 9.5, 1 (viii)
Ex 9.5, 1 (ix) Important
Ex 9.5, 1 (x)
Ex 9.5, 2 (i)
Ex 9.5, 2 (ii)
Ex 9.5, 2 (iii)
Ex 9.5, 2 (iv) Important
Ex 9.5, 2 (v)
Ex 9.5, 2 (vi) Important
Ex 9.5, 2 (vii) Important
Ex 9.5, 3 (i)
Ex 9.5, 3 (ii) Important
Ex 9.5, 3 (iii)
Ex 9.5, 3 (iv) Important
Ex 9.5, 3 (v) Important
Ex 9.5, 3 (vi)
Ex 9.5, 4 (i)
Ex 9.5, 4 (ii)
Ex 9.5, 4 (iii) Important
Ex 9.5, 4 (iv)
Ex 9.5, 4 (v) Important
Ex 9.5, 4 (vi)
Ex 9.5, 4 (vii) Important
Ex 9.5, 5 (i)
Ex 9.5, 5 (ii)
Ex 9.5, 5 (iii) Important
Ex 9.5, 5 (iv)
Ex 9.5, 5 (v) Important
Ex 9.5, 6 (i)
Ex 9.5, 6 (ii) Important
Ex 9.5, 6 (iii)
Ex 9.5, 6 (iv)
Ex 9.5, 6 (v) Important
Ex 9.5, 6 (vi)
Ex 9.5, 6 (vii) Important
Ex 9.5, 6 (viii)
Ex 9.5, 6 (ix) Important
Ex 9.5, 7 (i)
Ex 9.5, 7 (ii) Important
Ex 9.5, 7 (iii)
Ex 9.5, 7 (iv) Important
Ex 9.5, 8 (i)
Ex 9.5, 8 (ii)
Ex 9.5, 8 (iii) Important
Ex 9.5, 8 (iv) Important You are here
Transcript
Ex 9.5, 8 Using (π₯+π)(π₯+π)=π₯^2+(π+π)π₯+ππ , find (iv) 9.7 Γ 9.8 9.7 Γ9.8 = (10β0.3)Γ(10β0.2) = (10+(β0.3))Γ[10+(β0.2)] (π₯+π)(π₯+π)=π₯^2+(π+π)π₯+ππ Putting π₯ = 10 , π = β0.3 & π = β0.2 = (10)^2+(β0.3β0.2)(10)+(β0.3)(β0.2) = 100+(β0.5Γ10)+(0.3Γ0.2) = 100β(5/10Γ10)+(3/10Γ2/10) = 100β5+6/100 = 95+0.06 = ππ.ππ
