# Ex 9.5, 2 (ii) - Chapter 9 Class 8 Algebraic Expressions and Identities

Last updated at Sept. 8, 2021 by Teachoo

Last updated at Sept. 8, 2021 by Teachoo

Transcript

Ex 9.5, 2 Use the identity (π₯+π)(π₯+π)=π₯^2+(π+π)π₯+ππ to find the following products. (ii) (4π₯+5)(4π₯+1) (4π₯+5)(4π₯+1) (π¦+π)(π¦+π)=π¦^2+(π+π)π¦+ππ Putting π¦ = 4π₯ , π = 5 & π = 1 = (4π₯)^2+(5+1)(4π₯)+(5)(1) = (4^2Γπ₯^2 )+(6Γ4)π₯+5 = πππ^π+πππ+π

Ex 9.5

Ex 9.5, 1 (i)
Important

Ex 9.5, 1 (ii)

Ex 9.5, 1 (iii)

Ex 9.5, 1 (iv)

Ex 9.5, 1 (v)

Ex 9.5, 1 (vi)

Ex 9.5, 1 (vii)

Ex 9.5, 1 (viii)

Ex 9.5, 1 (ix)

Ex 9.5, 1 (x)

Ex 9.5, 2 (i)

Ex 9.5, 2 (ii) You are here

Ex 9.5, 2 (iii)

Ex 9.5, 2 (iv)

Ex 9.5, 2 (v)

Ex 9.5, 2 (vi)

Ex 9.5, 2 (vii)

Ex 9.5, 3 (i)

Ex 9.5, 3 (ii)

Ex 9.5, 3 (iii)

Ex 9.5, 3 (iv)

Ex 9.5, 3 (v)

Ex 9.5, 3 (vi)

Ex 9.5, 4 (i)

Ex 9.5, 4 (ii)

Ex 9.5, 4 (iii)

Ex 9.5, 4 (iv)

Ex 9.5, 4 (v)

Ex 9.5, 4 (vi)

Ex 9.5, 4 (vii)

Ex 9.5, 5 (i) Important

Ex 9.5, 5 (ii)

Ex 9.5, 5 (iii)

Ex 9.5, 5 (iv)

Ex 9.5, 5 (v)

Ex 9.5, 6 (i) Important

Ex 9.5, 6 (ii)

Ex 9.5, 6 (iii)

Ex 9.5, 6 (iv)

Ex 9.5, 6 (v)

Ex 9.5, 6 (vi)

Ex 9.5, 6 (vii)

Ex 9.5, 6 (viii)

Ex 9.5, 6 (ix)

Ex 9.5, 7 (i)

Ex 9.5, 7 (ii)

Ex 9.5, 7 (iii)

Ex 9.5, 7 (iv)

Ex 9.5, 8 (i) Important

Ex 9.5, 8 (ii)

Ex 9.5, 8 (iii)

Ex 9.5, 8 (iv)

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.