Ex 9.5, 2 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 2

Advertisement

  1. Chapter 9 Class 8 Algebraic Expressions and Identities
  2. Serial order wise

Transcript

Ex 9.5, 2 Use the identity (π‘₯+π‘Ž)(π‘₯+𝑏)=π‘₯^2+(π‘Ž+𝑏)π‘₯+π‘Žπ‘ to find the following products. (ii) (4π‘₯+5)(4π‘₯+1) (4π‘₯+5)(4π‘₯+1) (𝑦+π‘Ž)(𝑦+𝑏)=𝑦^2+(π‘Ž+𝑏)𝑦+π‘Žπ‘ Putting 𝑦 = 4π‘₯ , π‘Ž = 5 & 𝑏 = 1 = (4π‘₯)^2+(5+1)(4π‘₯)+(5)(1) = (4^2Γ—π‘₯^2 )+(6Γ—4)π‘₯+5 = πŸπŸ”π’™^𝟐+πŸπŸ’π’™+πŸ“

About the Author

Davneet Singh's photo - Teacher, Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.