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Ex 9.5, 7 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 2

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Ex 9.5, 7 Using π‘Ž^2βˆ’π‘^2=(π‘Ž+𝑏)(π‘Žβˆ’π‘) , find (ii) (1.02)^2βˆ’(0.98)^2 (1.02)^2βˆ’(0.98)^2 π‘Ž^2βˆ’π‘^2=(π‘Ž+𝑏)(π‘Žβˆ’π‘) Putting π‘Ž = 1.02 & 𝑏 = 0.98 = (1.02+0.98)Γ—(1.02βˆ’0.98) = 2Γ—0.04 = 2Γ—4/100 = 8/100 = 𝟎.πŸŽπŸ–

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