Ex 9.5, 7 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 2

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  1. Chapter 9 Class 8 Algebraic Expressions and Identities
  2. Serial order wise

Transcript

Ex 9.5, 7 Using ๐‘Ž^2โˆ’๐‘^2=(๐‘Ž+๐‘)(๐‘Žโˆ’๐‘) , find (ii) (1.02)^2โˆ’(0.98)^2 (1.02)^2โˆ’(0.98)^2 ๐‘Ž^2โˆ’๐‘^2=(๐‘Ž+๐‘)(๐‘Žโˆ’๐‘) Putting ๐‘Ž = 1.02 & ๐‘ = 0.98 = (1.02+0.98)ร—(1.02โˆ’0.98) = 2ร—0.04 = 2ร—4/100 = 8/100 = ๐ŸŽ.๐ŸŽ๐Ÿ–

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