Ex 9.5, 5 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 2

Advertisement

  1. Chapter 9 Class 8 Algebraic Expressions and Identities
  2. Serial order wise

Transcript

Ex 9.5, 5 Show that. (ii) (9π‘βˆ’5π‘ž)^2+180π‘π‘ž=(9𝑝+5π‘ž)^2 Solving LHS (9π‘βˆ’5π‘ž)^2+180π‘π‘ž (π‘Žβˆ’π‘)^2=π‘Ž^2+𝑏^2βˆ’2π‘Žπ‘ Putting π‘Ž = 9𝑝 & 𝑏 = 5π‘ž (π‘Žβˆ’π‘)^2=π‘Ž^2+𝑏^2βˆ’2π‘Žπ‘ Putting π‘Ž = 9𝑝 & 𝑏 = 5π‘ž Solving RHS (9𝑝+5π‘ž)^2 (π‘Ž+𝑏)^2=π‘Ž^2+𝑏^2+2π‘Žπ‘ Putting π‘Ž = 9𝑝 & 𝑏 = 5π‘ž = (9𝑝)^2+(5π‘ž)^2+2(9𝑝)(5π‘ž) = 81𝑝^2+25π‘ž^2+90π‘π‘ž Thus LHS = RHS Hence proved

About the Author

Davneet Singh's photo - Teacher, Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.