Question 5 (ii) - Algebra Identities and Formulas - Chapter 8 Class 8 Algebraic Expressions and Identities
Last updated at April 16, 2024 by Teachoo
Algebra Identities and Formulas
Question 1 (ii) Important
Question 1 (iii)
Question 1 (iv)
Question 1 (v) Important
Question 1 (vi) Important
Question 1 (vii)
Question 1 (viii)
Question 1 (ix) Important
Question 1 (x)
Question 2 (i)
Question 2 (ii)
Question 2 (iii)
Question 2 (iv) Important
Question 2 (v)
Question 2 (vi) Important
Question 2 (vii) Important
Question 3 (i)
Question 3 (ii) Important
Question 3 (iii)
Question 3 (iv) Important
Question 3 (v) Important
Question 3 (vi)
Question 4 (i)
Question 4 (ii)
Question 4 (iii) Important
Question 4 (iv)
Question 4 (v) Important
Question 4 (vi)
Question 4 (vii) Important
Question 5 (i)
Question 5 (ii) You are here
Question 5 (iii) Important
Question 5 (iv)
Question 5 (v) Important
Question 6 (i)
Question 6 (ii) Important
Question 6 (iii)
Question 6 (iv)
Question 6 (v) Important
Question 6 (vi)
Question 6 (vii) Important
Question 6 (viii)
Question 6 (ix) Important
Question 7 (i)
Question 7 (ii) Important
Question 7 (iii)
Question 7 (iv) Important
Question 8 (i)
Question 8 (ii)
Question 8 (iii) Important
Question 8 (iv) Important
Last updated at April 16, 2024 by Teachoo
Question 5 Show that. (ii) (9𝑝−5𝑞)^2+180𝑝𝑞=(9𝑝+5𝑞)^2 Solving LHS (9𝑝−5𝑞)^2+180𝑝𝑞 (𝑎−𝑏)^2=𝑎^2+𝑏^2−2𝑎𝑏 Putting 𝑎 = 9𝑝 & 𝑏 = 5𝑞 (𝑎−𝑏)^2=𝑎^2+𝑏^2−2𝑎𝑏 Putting 𝑎 = 9𝑝 & 𝑏 = 5𝑞 Solving RHS (9𝑝+5𝑞)^2 (𝑎+𝑏)^2=𝑎^2+𝑏^2+2𝑎𝑏 Putting 𝑎 = 9𝑝 & 𝑏 = 5𝑞 = (9𝑝)^2+(5𝑞)^2+2(9𝑝)(5𝑞) = 81𝑝^2+25𝑞^2+90𝑝𝑞 Thus LHS = RHS Hence proved