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Ex 9.5, 5 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 2

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Ex 9.5, 5 Show that. (ii) (9π‘βˆ’5π‘ž)^2+180π‘π‘ž=(9𝑝+5π‘ž)^2 Solving LHS (9π‘βˆ’5π‘ž)^2+180π‘π‘ž (π‘Žβˆ’π‘)^2=π‘Ž^2+𝑏^2βˆ’2π‘Žπ‘ Putting π‘Ž = 9𝑝 & 𝑏 = 5π‘ž (π‘Žβˆ’π‘)^2=π‘Ž^2+𝑏^2βˆ’2π‘Žπ‘ Putting π‘Ž = 9𝑝 & 𝑏 = 5π‘ž Solving RHS (9𝑝+5π‘ž)^2 (π‘Ž+𝑏)^2=π‘Ž^2+𝑏^2+2π‘Žπ‘ Putting π‘Ž = 9𝑝 & 𝑏 = 5π‘ž = (9𝑝)^2+(5π‘ž)^2+2(9𝑝)(5π‘ž) = 81𝑝^2+25π‘ž^2+90π‘π‘ž Thus LHS = RHS Hence proved

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.