Ex 9.5, 5 Show that. (ii) (9𝑝−5𝑞)^2+180𝑝𝑞=(9𝑝+5𝑞)^2 Solving LHS (9𝑝−5𝑞)^2+180𝑝𝑞 (𝑎−𝑏)^2=𝑎^2+𝑏^2−2𝑎𝑏 Putting 𝑎 = 9𝑝 & 𝑏 = 5𝑞 (𝑎−𝑏)^2=𝑎^2+𝑏^2−2𝑎𝑏 Putting 𝑎 = 9𝑝 & 𝑏 = 5𝑞 Solving RHS (9𝑝+5𝑞)^2 (𝑎+𝑏)^2=𝑎^2+𝑏^2+2𝑎𝑏 Putting 𝑎 = 9𝑝 & 𝑏 = 5𝑞 = (9𝑝)^2+(5𝑞)^2+2(9𝑝)(5𝑞) = 81𝑝^2+25𝑞^2+90𝑝𝑞 Thus LHS = RHS Hence proved

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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