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Ex 9.5, 4 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 11

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Ex 9.5, 4 Simplify. (vii) (π‘š^2βˆ’π‘›^2 π‘š)^2+2π‘š^3 𝑛^2 (π‘š^2βˆ’π‘›^2 π‘š)^2+2π‘š^3 𝑛^2 (π‘Žβˆ’π‘)^2=π‘Ž^2+𝑏^2βˆ’2π‘Žπ‘ Putting π‘Ž = π‘š^2 & 𝑏 = 𝑛^2 π‘š = (π‘š^2 )^2+(𝑛^2 π‘š)^2βˆ’2(π‘š^2 )(𝑛^2 π‘š)+2π‘š^3 𝑛^2 = π‘š^(2 Γ— 2)+(𝑛^2 )^2Γ—π‘š^2βˆ’2Γ—(π‘š^2Γ—π‘š)×𝑛^2+2π‘š^3 𝑛^2 = π‘š^4+𝑛^4 π‘š^2βˆ’2π‘š^3 𝑛^2+2π‘š^3 𝑛^2 = π’Ž^πŸ’+𝒏^πŸ’ π’Ž^𝟐

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.