Ex 9.5, 8 (iii) - Chapter 9 Class 8 Algebraic Expressions and Identities
Last updated at Sept. 8, 2021 by
Transcript
Ex 9.5, 8 Using (π₯+π)(π₯+π)=π₯^2+(π+π)π₯+ππ , find (iii) 103 Γ 98 103 Γ98 = (100+3)Γ(100β2) = (100+3)Γ[100+(β2)] (π₯+π)(π₯+π)=π₯^2+(π+π)π₯+ππ Putting π₯ = 100 , π = 3 & π = β2 = (100)^2+(3+2)(100)+(3)(β2) = 10000+100β6 = 10000+94 = πππππ
Ex 9.5
Ex 9.5, 1 (i)
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Ex 9.5, 1 (iii)
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Ex 9.5, 8 (i)
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Ex 9.5, 8 (iii) Important You are here
Ex 9.5, 8 (iv) Important
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