# Ex 9.5, 8 (iii) - Chapter 9 Class 8 Algebraic Expressions and Identities

Last updated at Sept. 8, 2021 by Teachoo

Last updated at Sept. 8, 2021 by Teachoo

Transcript

Ex 9.5, 8 Using (π₯+π)(π₯+π)=π₯^2+(π+π)π₯+ππ , find (iii) 103 Γ 98 103 Γ98 = (100+3)Γ(100β2) = (100+3)Γ[100+(β2)] (π₯+π)(π₯+π)=π₯^2+(π+π)π₯+ππ Putting π₯ = 100 , π = 3 & π = β2 = (100)^2+(3+2)(100)+(3)(β2) = 10000+100β6 = 10000+94 = πππππ

Ex 9.5

Ex 9.5, 1 (i)
Important

Ex 9.5, 1 (ii)

Ex 9.5, 1 (iii)

Ex 9.5, 1 (iv)

Ex 9.5, 1 (v)

Ex 9.5, 1 (vi)

Ex 9.5, 1 (vii)

Ex 9.5, 1 (viii)

Ex 9.5, 1 (ix)

Ex 9.5, 1 (x)

Ex 9.5, 2 (i)

Ex 9.5, 2 (ii)

Ex 9.5, 2 (iii)

Ex 9.5, 2 (iv)

Ex 9.5, 2 (v)

Ex 9.5, 2 (vi)

Ex 9.5, 2 (vii)

Ex 9.5, 3 (i)

Ex 9.5, 3 (ii)

Ex 9.5, 3 (iii)

Ex 9.5, 3 (iv)

Ex 9.5, 3 (v)

Ex 9.5, 3 (vi)

Ex 9.5, 4 (i)

Ex 9.5, 4 (ii)

Ex 9.5, 4 (iii)

Ex 9.5, 4 (iv)

Ex 9.5, 4 (v)

Ex 9.5, 4 (vi)

Ex 9.5, 4 (vii)

Ex 9.5, 5 (i) Important

Ex 9.5, 5 (ii)

Ex 9.5, 5 (iii)

Ex 9.5, 5 (iv)

Ex 9.5, 5 (v)

Ex 9.5, 6 (i) Important

Ex 9.5, 6 (ii)

Ex 9.5, 6 (iii)

Ex 9.5, 6 (iv)

Ex 9.5, 6 (v)

Ex 9.5, 6 (vi)

Ex 9.5, 6 (vii)

Ex 9.5, 6 (viii)

Ex 9.5, 6 (ix)

Ex 9.5, 7 (i)

Ex 9.5, 7 (ii)

Ex 9.5, 7 (iii)

Ex 9.5, 7 (iv)

Ex 9.5, 8 (i) Important

Ex 9.5, 8 (ii)

Ex 9.5, 8 (iii) You are here

Ex 9.5, 8 (iv)

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.