Ex 9.5, 8 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 3

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  1. Chapter 9 Class 8 Algebraic Expressions and Identities
  2. Serial order wise

Transcript

Ex 9.5, 8 Using (π‘₯+π‘Ž)(π‘₯+𝑏)=π‘₯^2+(π‘Ž+𝑏)π‘₯+π‘Žπ‘ , find (iii) 103 Γ— 98 103 Γ—98 = (100+3)Γ—(100βˆ’2) = (100+3)Γ—[100+(βˆ’2)] (π‘₯+π‘Ž)(π‘₯+𝑏)=π‘₯^2+(π‘Ž+𝑏)π‘₯+π‘Žπ‘ Putting π‘₯ = 100 , π‘Ž = 3 & 𝑏 = βˆ’2 = (100)^2+(3+2)(100)+(3)(βˆ’2) = 10000+100βˆ’6 = 10000+94 = πŸπŸŽπŸŽπŸ—πŸ’

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.