Question 8 (iii) - Algebra Identities and Formulas - Chapter 8 Class 8 Algebraic Expressions and Identities

Last updated at Dec. 16, 2024 by

Ex 9.5, 8 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 3

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Question 8 Using (𝑥+𝑎)(𝑥+𝑏)=𝑥^2+(𝑎+𝑏)𝑥+𝑎𝑏 , find (iii) 103 × 98 103 ×98 = (100+3)×(100−2) = (100+3)×[100+(−2)] (𝑥+𝑎)(𝑥+𝑏)=𝑥^2+(𝑎+𝑏)𝑥+𝑎𝑏 Putting 𝑥 = 100 , 𝑎 = 3 & 𝑏 = −2 = (100)^2+(3+2)(100)+(3)(−2) = 10000+100−6 = 10000+94 = 𝟏𝟎𝟎𝟗𝟒

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo