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Ex 9.5, 2 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 4

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Ex 9.5, 2 Use the identity (π‘₯+π‘Ž)(π‘₯+𝑏)=π‘₯^2+(π‘Ž+𝑏)π‘₯+π‘Žπ‘ to find the following products. (iv) (4π‘₯+5)(4π‘₯βˆ’1) (4π‘₯+5)(4π‘₯βˆ’1) = (4π‘₯+5) (4π‘₯+(βˆ’1)) (𝑦+π‘Ž)(𝑦+𝑏)=𝑦^2+(π‘Ž+𝑏)𝑦+π‘Žπ‘ Putting 𝑦 = 4π‘₯ , π‘Ž = 5 & 𝑏 = βˆ’1 (𝑦+π‘Ž)(𝑦+𝑏)=𝑦^2+(π‘Ž+𝑏)𝑦+π‘Žπ‘ Putting 𝑦 = 4π‘₯ , π‘Ž = 5 & 𝑏 = βˆ’1

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