Ex 9.5, 5 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 7

Ex 9.5, 5 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 8

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Question 5 Show that. (v) (𝑎−𝑏) (𝑎+𝑏)+(𝑏−𝑐)(𝑏+𝑐)+(𝑐−𝑎)(𝑐+𝑎)=0 Solving LHS (𝑎−𝑏) (𝑎+𝑏)+(𝑏−𝑐)(𝑏+𝑐)+(𝑐−𝑎)(𝑐+𝑎) Using (𝑥−𝑦)(𝑥+𝑦)=𝑥^2+𝑦^2 = (𝑎^2−𝑏^2 )+(𝑏^2−𝑐^2 )+(𝑏^2−𝑐^2 ) = 𝑎^2−𝑏^2+𝑏^2−𝑐^2+𝑐^2−𝑎^2 = (𝑎^2−𝑎^2 )+(−𝑏^2+𝑏^2 )+(−𝑐^2+𝑐^2 ) = 0+0+0 = 0 = R.H.S Since LHS = RHS Hence proved

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