Check sibling questions

Ex 9.5, 5 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 7

Ex 9.5, 5 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 8

Introducing your new favourite teacher - Teachoo Black, at only β‚Ή83 per month


Transcript

Ex 9.5, 5 Show that. (v) (π‘Žβˆ’π‘) (π‘Ž+𝑏)+(π‘βˆ’π‘)(𝑏+𝑐)+(π‘βˆ’π‘Ž)(𝑐+π‘Ž)=0 Solving LHS (π‘Žβˆ’π‘) (π‘Ž+𝑏)+(π‘βˆ’π‘)(𝑏+𝑐)+(π‘βˆ’π‘Ž)(𝑐+π‘Ž) Using (π‘₯βˆ’π‘¦)(π‘₯+𝑦)=π‘₯^2+𝑦^2 = (π‘Ž^2βˆ’π‘^2 )+(𝑏^2βˆ’π‘^2 )+(𝑏^2βˆ’π‘^2 ) = π‘Ž^2βˆ’π‘^2+𝑏^2βˆ’π‘^2+𝑐^2βˆ’π‘Ž^2 = (π‘Ž^2βˆ’π‘Ž^2 )+(βˆ’π‘^2+𝑏^2 )+(βˆ’π‘^2+𝑐^2 ) = 0+0+0 = 0 = R.H.S Since LHS = RHS Hence proved

Davneet Singh's photo - Teacher, Engineer, Marketer

Made by

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.