Question 6 (ii) - Algebra Identities and Formulas - Chapter 8 Class 8 Algebraic Expressions and Identities
Last updated at Dec. 16, 2024 by Teachoo
Algebra Identities and Formulas
Last updated at Dec. 16, 2024 by Teachoo
Transcript
Question 6 Using identities, evaluate. (ii) 〖99〗^2 〖99〗^2 =(100−1)^2 (𝑎−𝑏)^2=𝑎^2+𝑏^2−2𝑎𝑏 Putting 𝑎 = 100 & 𝑏 = 1 = (100)^2+(1)^2−2(100)(1) = 10000+1−200 = 10001−200 = 𝟗𝟖𝟎𝟏