Question 6 (ii) - Algebra Identities and Formulas - Chapter 8 Class 8 Algebraic Expressions and Identities

Last updated at August 14, 2026 by

Ex 9.5, 6 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 2

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Question 6 Using identities, evaluate. (ii) 〖99〗^2 〖99〗^2 =(100−1)^2 (𝑎−𝑏)^2=𝑎^2+𝑏^2−2𝑎𝑏 Putting 𝑎 = 100 & 𝑏 = 1 = (100)^2+(1)^2−2(100)(1) = 10000+1−200 = 10001−200 = 𝟗𝟖𝟎𝟏

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