Ex 9.5, 6 Using identities, evaluate. (ii) 〖99〗^2 〖99〗^2 =(100−1)^2 (𝑎−𝑏)^2=𝑎^2+𝑏^2−2𝑎𝑏 Putting 𝑎 = 100 & 𝑏 = 1 = (100)^2+(1)^2−2(100)(1) = 10000+1−200 = 10001−200 = 𝟗𝟖𝟎𝟏

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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