# Ex 9.5, 3 (v) - Chapter 9 Class 8 Algebraic Expressions and Identities

Last updated at Sept. 8, 2021 by Teachoo

Ex 9.5

Ex 9.5, 1 (i)

Ex 9.5, 1 (ii) Important

Ex 9.5, 1 (iii)

Ex 9.5, 1 (iv)

Ex 9.5, 1 (v) Important

Ex 9.5, 1 (vi) Important

Ex 9.5, 1 (vii)

Ex 9.5, 1 (viii)

Ex 9.5, 1 (ix) Important

Ex 9.5, 1 (x)

Ex 9.5, 2 (i)

Ex 9.5, 2 (ii)

Ex 9.5, 2 (iii)

Ex 9.5, 2 (iv) Important

Ex 9.5, 2 (v)

Ex 9.5, 2 (vi) Important

Ex 9.5, 2 (vii) Important

Ex 9.5, 3 (i)

Ex 9.5, 3 (ii) Important

Ex 9.5, 3 (iii)

Ex 9.5, 3 (iv) Important

Ex 9.5, 3 (v) Important You are here

Ex 9.5, 3 (vi)

Ex 9.5, 4 (i)

Ex 9.5, 4 (ii)

Ex 9.5, 4 (iii) Important

Ex 9.5, 4 (iv)

Ex 9.5, 4 (v) Important

Ex 9.5, 4 (vi)

Ex 9.5, 4 (vii) Important

Ex 9.5, 5 (i)

Ex 9.5, 5 (ii)

Ex 9.5, 5 (iii) Important

Ex 9.5, 5 (iv)

Ex 9.5, 5 (v) Important

Ex 9.5, 6 (i)

Ex 9.5, 6 (ii) Important

Ex 9.5, 6 (iii)

Ex 9.5, 6 (iv)

Ex 9.5, 6 (v) Important

Ex 9.5, 6 (vi)

Ex 9.5, 6 (vii) Important

Ex 9.5, 6 (viii)

Ex 9.5, 6 (ix) Important

Ex 9.5, 7 (i)

Ex 9.5, 7 (ii) Important

Ex 9.5, 7 (iii)

Ex 9.5, 7 (iv) Important

Ex 9.5, 8 (i)

Ex 9.5, 8 (ii)

Ex 9.5, 8 (iii) Important

Ex 9.5, 8 (iv) Important

Last updated at Sept. 8, 2021 by Teachoo

Ex 9.5, 3 Find the following squares by using the identities. (v) (0.4πβ0.5π)^2 (0.4πβ0.5π)^2 (πβπ)^2=π^2+π^2β2ππ Putting π = 0.4π & π = 0.5π = (0.4π)^2+(0.5π)^2β2(0.4π)(0.5π) = (4/10)^2Γπ^2+(5/10)^2Γπ^2β(2Γ4/10Γ5/10)Γ(πΓπ) = 16/100 π^2+ 25/100 π^2β4/10 ππ = π.πππ^π+π.πππ^πβπ.πππ