Ex 9.5, 3 Find the following squares by using the identities. (v) (0.4𝑝−0.5𝑞)^2 (0.4𝑝−0.5𝑞)^2 (𝑎−𝑏)^2=𝑎^2+𝑏^2−2𝑎𝑏 Putting 𝑎 = 0.4𝑝 & 𝑏 = 0.5𝑞 = (0.4𝑝)^2+(0.5𝑞)^2−2(0.4𝑝)(0.5𝑞) = (4/10)^2×𝑝^2+(5/10)^2×𝑞^2−(2×4/10×5/10)×(𝑝×𝑞) = 16/100 𝑝^2+ 25/100 𝑞^2−4/10 𝑝𝑞 = 𝟎.𝟏𝟔𝒑^𝟐+𝟎.𝟐𝟓𝒒^𝟐−𝟎.𝟒𝒑𝒒

Next: Ex 9.5, 3 (vi) → Ask a doubt

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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