Algebra Identities and Formulas
Question 1 (ii) Important
Question 1 (iii)
Question 1 (iv)
Question 1 (v) Important
Question 1 (vi) Important
Question 1 (vii)
Question 1 (viii)
Question 1 (ix) Important
Question 1 (x)
Question 2 (i)
Question 2 (ii)
Question 2 (iii)
Question 2 (iv) Important
Question 2 (v)
Question 2 (vi) Important
Question 2 (vii) Important
Question 3 (i)
Question 3 (ii) Important
Question 3 (iii)
Question 3 (iv) Important
Question 3 (v) Important
Question 3 (vi)
Question 4 (i)
Question 4 (ii)
Question 4 (iii) Important
Question 4 (iv)
Question 4 (v) Important
Question 4 (vi)
Question 4 (vii) Important
Question 5 (i) You are here
Question 5 (ii)
Question 5 (iii) Important
Question 5 (iv)
Question 5 (v) Important
Question 6 (i)
Question 6 (ii) Important
Question 6 (iii)
Question 6 (iv)
Question 6 (v) Important
Question 6 (vi)
Question 6 (vii) Important
Question 6 (viii)
Question 6 (ix) Important
Question 7 (i)
Question 7 (ii) Important
Question 7 (iii)
Question 7 (iv) Important
Question 8 (i)
Question 8 (ii)
Question 8 (iii) Important
Question 8 (iv) Important
Last updated at April 16, 2024 by Teachoo
Question 5 Show that. (i) (3𝑥+7)^2−84𝑥=(3𝑥−7)^2 Solving LHS (3𝑥+7)^2−84𝑥 = (3𝑥)^2+(7)^2+ 2(3𝑥)(7)−84𝑥 = 9𝑥^2+49+42𝑥−84𝑥 = 9𝑥^2+49−42𝑥 (𝑎+𝑏)^2=𝑎^2+𝑏^2−2𝑎𝑏 Putting 𝑎 = 3𝑥 & 𝑏 = 7 = (3𝑥)^2+(7)^2+ 2(3𝑥)(7)−84𝑥 = 9𝑥^2+49+42𝑥−84𝑥 = 9𝑥^2+49−42𝑥 Solving RHS (3𝑥−7)^2 (𝑎−𝑏)^2=𝑎^2+𝑏^2−2𝑎𝑏 Putting 𝑎 = 3𝑥 & 𝑏 = 7 = (3𝑥)^2+(7)^2−2(3𝑥)(7) = (3^2×𝑥^2 )+49−(2×3×7)𝑥 = 9𝑥^2+49−42𝑥 Thus LHS = RHS Hence proved