Question 2 (iii) - Algebra Identities and Formulas - Chapter 8 Class 8 Algebraic Expressions and Identities
Last updated at Dec. 16, 2024 by Teachoo
Algebra Identities and Formulas
Last updated at Dec. 16, 2024 by Teachoo
Question 2 Use the identity (𝑥+𝑎)(𝑥+𝑏)=𝑥^2+(𝑎+𝑏)𝑥+𝑎𝑏 to find the following products. (iii) (4𝑥−5)(4𝑥−1) (4𝑥−5)(4𝑥−1) = [4𝑥+(−5)][4𝑥+(−1)] (𝑦+𝑎)(𝑦+𝑏)=𝑦^2+(𝑎+𝑏)𝑦+𝑎𝑏 Putting 𝑦 = 4𝑥 , 𝑎 = −5 & 𝑏 = −1 = (4𝑥)^2+(−5−1)(4𝑥)+(−5)(−1) = (4^2×𝑥^2 )+(−6)(4𝑥)+5 = 𝟏𝟔𝒙^𝟐−𝟐𝟒𝒙+𝟓