Ex 9.5, 6 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 11

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Ex 9.5, 6 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 12

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  1. Chapter 9 Class 8 Algebraic Expressions and Identities
  2. Serial order wise

Transcript

Ex 9.5, 6 Using identities, evaluate. (ix) 1.05×9.5 1.05×9.5 = 105/100×95/10 = (105 × 95)/1000 = ((100 + 5) × (100 − 5))/1000 (𝑎+𝑏)(𝑎−𝑏)=𝑎^2−𝑏^2 Putting 𝑎 = 100 & 𝑏 = 5 = ((100)^2 − (5)^2)/1000 = (10000 − 25)/1000 = 9975/1000 = 9.975

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