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Ex 9.5, 2 (vi) - Chapter 9 Class 8 Algebraic Expressions and Identities
Last updated at March 22, 2023 by Teachoo
Ex 9.5
Ex 9.5, 1 (i)
Ex 9.5, 1 (ii) Important
Ex 9.5, 1 (iii)
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Ex 9.5, 1 (x)
Ex 9.5, 2 (i)
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Ex 9.5, 2 (v)
Ex 9.5, 2 (vi) Important You are here
Ex 9.5, 2 (vii) Important
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Ex 9.5, 8 (i)
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Transcript
Ex 9.5, 2 Use the identity (π₯+π)(π₯+π)=π₯^2+(π+π)π₯+ππ to find the following products. (vi) (2π^2+9) (2π^2+5) (2π^2+9) (2π^2+5) (π₯+π)(π₯+π)=π₯^2+(π+π)π₯+ππ Putting π₯ = 2π^2 , π = 9 & π = 5 = (2π^2 )^2+(9+5)(2π^2 )+(9)(5) = (2^2Γπ^(2 Γ 2) )+(14Γ2) π^2+45 = ππ^π+πππ^π+ππ
