Ex 9.5, 4 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 6

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  1. Chapter 9 Class 8 Algebraic Expressions and Identities
  2. Serial order wise

Transcript

Ex 9.5, 4 Simplify. (iv) (4π‘š+5𝑛)^2+(5π‘š+4𝑛)^2 Solving (πŸ’π’Ž+πŸ“π’)^𝟐 (π‘Ž+𝑏)^2=π‘Ž^2+𝑏^2+2π‘Žπ‘ Putting π‘Ž = 4π‘š & 𝑏 = 5𝑛 = (4π‘š)^2+(5𝑛)^2+2(4π‘š)(5𝑛) = 16π‘š^2+25𝑛^2+40π‘šπ‘› Solving (πŸ“π’Ž+πŸ’π’)^𝟐 (π‘Ž+𝑏)^2=π‘Ž^2+𝑏^2+2π‘Žπ‘ Putting π‘Ž = 5π‘š & 𝑏 = 4𝑛 = (5π‘š)^2+(4𝑛)^2+2(5π‘š)(4𝑛) = 25π‘š^2+16𝑛^2+40π‘šπ‘› ∴ (4π‘š+5𝑛)^2+(5π‘š+4𝑛)^2 = (16π‘š^2+25𝑛^2+40π‘šπ‘›)+(25π‘š^2+16𝑛^2+40π‘šπ‘›) = (16π‘š^2+25π‘š^2 )+(25𝑛^2+16𝑛^2 )+(40π‘šπ‘›+40π‘šπ‘›) = πŸ’πŸπ’Ž^𝟐+πŸ’πŸπ’^𝟐+πŸ–πŸŽπ’Žπ’

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.