# Ex 9.5, 8 (ii) - Chapter 9 Class 8 Algebraic Expressions and Identities

Last updated at Sept. 8, 2021 by Teachoo

Last updated at Sept. 8, 2021 by Teachoo

Transcript

Ex 9.5, 8 Using (π₯+π)(π₯+π)=π₯^2+(π+π)π₯+ππ , find (ii) 5.1 Γ 5.2 5.1 Γ 5.2 = (5+0.1)Γ(5+0.2) (π₯+π)(π₯+π)=π₯^2+(π+π)π₯+ππ Putting π₯ = 5 , π = 0.1 & π = 0.2 = (5)^2+(0.1+0.2)(5)+(0.1)(0.2) = 25+(0.3)5+(0.1Γ0.2) = 25+3/10Γ5+(1/10Γ2/10) = 25+(15/10)+2/100 = 25+1.5+0.02 = ππ.ππ

Ex 9.5

Ex 9.5, 1 (i)
Important

Ex 9.5, 1 (ii)

Ex 9.5, 1 (iii)

Ex 9.5, 1 (iv)

Ex 9.5, 1 (v)

Ex 9.5, 1 (vi)

Ex 9.5, 1 (vii)

Ex 9.5, 1 (viii)

Ex 9.5, 1 (ix)

Ex 9.5, 1 (x)

Ex 9.5, 2 (i)

Ex 9.5, 2 (ii)

Ex 9.5, 2 (iii)

Ex 9.5, 2 (iv)

Ex 9.5, 2 (v)

Ex 9.5, 2 (vi)

Ex 9.5, 2 (vii)

Ex 9.5, 3 (i)

Ex 9.5, 3 (ii)

Ex 9.5, 3 (iii)

Ex 9.5, 3 (iv)

Ex 9.5, 3 (v)

Ex 9.5, 3 (vi)

Ex 9.5, 4 (i)

Ex 9.5, 4 (ii)

Ex 9.5, 4 (iii)

Ex 9.5, 4 (iv)

Ex 9.5, 4 (v)

Ex 9.5, 4 (vi)

Ex 9.5, 4 (vii)

Ex 9.5, 5 (i) Important

Ex 9.5, 5 (ii)

Ex 9.5, 5 (iii)

Ex 9.5, 5 (iv)

Ex 9.5, 5 (v)

Ex 9.5, 6 (i) Important

Ex 9.5, 6 (ii)

Ex 9.5, 6 (iii)

Ex 9.5, 6 (iv)

Ex 9.5, 6 (v)

Ex 9.5, 6 (vi)

Ex 9.5, 6 (vii)

Ex 9.5, 6 (viii)

Ex 9.5, 6 (ix)

Ex 9.5, 7 (i)

Ex 9.5, 7 (ii)

Ex 9.5, 7 (iii)

Ex 9.5, 7 (iv)

Ex 9.5, 8 (i) Important

Ex 9.5, 8 (ii) You are here

Ex 9.5, 8 (iii)

Ex 9.5, 8 (iv)

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.