Ex 9.5, 2 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 7

Remove Ads

Transcript

Question 2 Use the identity (๐‘ฅ+๐‘Ž)(๐‘ฅ+๐‘)=๐‘ฅ^2+(๐‘Ž+๐‘)๐‘ฅ+๐‘Ž๐‘ to find the following products. (vii) (๐‘ฅ๐‘ฆ๐‘งโˆ’4) (๐‘ฅ๐‘ฆ๐‘งโˆ’2) (๐‘ฅ๐‘ฆ๐‘งโˆ’4) (๐‘ฅ๐‘ฆ๐‘งโˆ’2) = (๐‘ฅ๐‘ฆ๐‘ง+(โˆ’4)) (๐‘ฅ๐‘ฆ๐‘ง+(โˆ’2)) (๐‘ก+๐‘Ž)(๐‘ก+๐‘)=๐‘ก^2+(๐‘Ž+๐‘)๐‘ก+๐‘Ž๐‘ Putting ๐‘ก = ๐‘ฅ๐‘ฆ๐‘ง , ๐‘Ž = โˆ’4 & ๐‘ = โˆ’2 = (๐‘)^2+(7)^2โˆ’2(๐‘)(7) = ๐‘^2+49โˆ’(2ร—7)ร—๐‘ = ๐’ƒ^๐Ÿ+๐Ÿ’๐Ÿ—โˆ’๐Ÿ๐Ÿ’๐’ƒ

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.