Example 27 (Supplementary NCERT) - Chapter 10 Class 12 Vector Algebra
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Example 27 (Supplementary NCERT) Show that the vectors π β = π Μ β 2π Μ + 3π Μ, π β = β2π Μ + 3π Μ β 4π Μ and π β = π Μ β 3π Μ + 5π Μ are coplanarThree vectors π β, π β, π β are coplanar if [π β" " π β" " π β ] = 0 Given, π β = π Μ β 2π Μ + 3π Μ π β = β2π Μ + 3π Μ β 4π Μ π β = π Μ β 3π Μ + Ξ»π Μ [π β" " π β" " π β ] = |β 8(1&β2&3@β2&3&β4@1&β3&5)| = 1[(3Γ5)β(β3Γβ4) ] β (β2) [(β2Γ5)β(1Γβ4) ] + 3[(β2Γβ3)β(1Γ3) ] = 1 [15β(3 Γ4)]+2[β10β(β4)]+3[(2 Γ3)β3] = 1 [15β12]+2[β10+4]+3[6β3] = 1 [3]+2[β6]+3[3] = 3 β 12 + 9 = 0 Since [π β" " π β" " π β ] = 0 Vectors π β, π β, π β are coplanar
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Example 26 (Supplementary NCERT)
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Example 28 (Supplementary NCERT) Important
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo