Example 9 - Chapter 10 Class 12 Vector Algebra
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Example 9 Write the direction ratioβs of the vector π β = π Μ + π Μ β 2π Μ and hence calculate its direction cosines. Given π β = π Μ + π Μ β 2π Μ = 1π Μ + 1π Μ β 2π Μ Directions ratios are π = 1 , b = 1 , c = β2 Magnitude of π β = β(1^2+1^2+(β2)^2 ) |π| = β(1+1+4) = βπ The directions cosines of π β are (π/|π β | ,π/|π β | ,π/|π β | ) = (π/βπ,π/βπ,(βπ)/βπ)
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo