# Misc 15 (MCQ) - Chapter 9 Class 12 Differential Equations

Last updated at April 16, 2024 by Teachoo

Miscellaneous

Misc 1 (i)

Misc 1 (ii)

Misc 1 (iii) Important

Misc 2 (i)

Misc 2 (ii) Important

Misc 2 (iii)

Misc 2 (iv) Important

Misc 3 Important

Misc 4

Misc 5 Important

Misc 6

Misc 7 Important

Misc 8 Important

Misc 9

Misc 10 Important

Misc 11

Misc 12 Important

Misc 13 (MCQ)

Misc 14 (MCQ) Important

Misc 15 (MCQ) You are here

Question 1 Deleted for CBSE Board 2025 Exams

Question 2 Important Deleted for CBSE Board 2025 Exams

Question 3 Important Deleted for CBSE Board 2025 Exams

Chapter 9 Class 12 Differential Equations

Serial order wise

Last updated at April 16, 2024 by Teachoo

Misc 15 The general solution of the differential equation π^π₯ ππ¦+(π¦ π^π₯+2π₯)ππ₯=0 is (A) π₯ π^π¦+π₯^2=πΆ (B) π₯ π^π¦+π¦^2=πΆ (C) π¦ π^π₯+π₯^2=πΆ (D) π¦ π^π¦+π₯^2=πΆ Given equation π^π₯ ππ¦+(π¦ π^π₯+2π₯)ππ₯=0 π^π π π=β(π π^π+ππ)π π ππ¦/ππ₯= (β(π¦π^π₯ + 2π₯))/π^π₯ ππ¦/ππ₯ = (βπ¦π^π₯)/π^π₯ β2π₯/π^π₯ ππ¦/ππ₯ = βπ¦β2π₯/π^π₯ π π/π π + y = (βππ)/π^π Differential equation is of the form ππ¦/ππ₯ + Py = Q where P = 1 & Q = (βππ)/π^π Now, IF = π^β«1βγπ ππ₯γ IF = π^β«1βγ1 ππ₯γ IF = π^π Solution is y(IF) = β«1βγ(πΓπΌπΉ)ππ₯+πγ yex = β«1βγ(βππ)/π^π π^π π π+πγ yex = ββ«1βγ2π₯ ππ₯+πγ yex = β2Γπ₯^2/2+π yex = βπ₯^2+π yex + π^π=π So, the correct answer is (c)