# Misc 10 - Chapter 9 Class 12 Differential Equations

Last updated at April 16, 2024 by Teachoo

Miscellaneous

Misc 1 (i)

Misc 1 (ii)

Misc 1 (iii) Important

Misc 2 (i)

Misc 2 (ii) Important

Misc 2 (iii)

Misc 2 (iv) Important

Misc 3 Important

Misc 4

Misc 5 Important

Misc 6

Misc 7 Important

Misc 8 Important

Misc 9

Misc 10 Important You are here

Misc 11

Misc 12 Important

Misc 13 (MCQ)

Misc 14 (MCQ) Important

Misc 15 (MCQ)

Question 1 Deleted for CBSE Board 2024 Exams

Question 2 Important Deleted for CBSE Board 2024 Exams

Question 3 Important Deleted for CBSE Board 2024 Exams

Chapter 9 Class 12 Differential Equations

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Last updated at April 16, 2024 by Teachoo

Misc 10 Solve the differential equation [š^(ā2āš„)/āš„āš¦/āš„] šš„/šš¦=1(š„ā 0)[š^(ā2āš„)/āš„āš¦/āš„] šš„/šš¦=1 š^(ā2āš„)/āš„ā š¦/āš„ =šš¦/šš„ š š/š š + š/āš = š^(āšāš)/āš Differential equation is of the form šš¦/šš„ + Py = Q where P = š/āš & Q = š^(āšāš)/āš IF. = eā«1ā"pdx" Finding ā«1āćš· š šć ā«1āćš· š š=ā«1āš š/āš ć ā«1āćš šš„=ā«1āćš„^((ā1)/2) šš„ć ć ā«1āćš šš„=ā«1āć(š„ (ā1)/2 + 1)/((ā1)/2 + 1) šš„ć ć ā«1āćš šš„=2š„^(1/2) ć= 2āš„ ā“ IF = š^(šāš) Solution is y (IF) = ā«1āć(šĆš¼š¹)šš„+šć yš^(šāš) = ā«1āć(š^(āšāš)/āšĆš^(šāš) )š š+šć yš^(2āš„) = ā«1āćšš„/āš„+šć yš^(2āš„) = ā«1āć1/āš„ šš„+šć yš^(2āš„) = ā«1āćš„^((ā1)/2) šš„+šć yš^(2āš„) = ā«1āć(š„^(ā1/2 + 1) )/(ā1/2 + 1)+šć "y" š^(2āš„) " = "2š„^(1/2) + C "y" š^(šāš) " = "2āš + C