Miscellaneous
Last updated at August 5, 2026 by Teachoo
Transcript
Misc 2 For each of the exercise given below , verify that the given function (šššššššš” šš šš„šššššš”) is a solution of the corresponding differential equation . (i) š„š¦=š š^š„+š š^(āš„)+š„^2 : š„ (š^2 š¦)/(šš„^2 )+2 šš¦/šš„āš„š¦+š„^2ā2=0 š„š¦=šš^š„+š š^(āš„)+š„^2 Differentiating w.r.t x (š(š„š¦))/šš„=š/šš„ [š š^š„+š š^(āš„)+š„^2 ] šš„/šš„ y+šš¦/šš„ š„ =šć šć^š„+(ā1)š š^(āš„)+2š„ š+š^ā² š =šć šć^šāš š^(āš)+šš Differentiating again w.r.t x š¦ā²+(š¦^ā² š„)^ā² =(šš^š„ )^ā²ā(šš^(āš„) )^ā²+(2š„)^ā² š¦^ā²+(š¦^ā²ā² š„+š¦^ā²Ć1)=šš^š„+šš^(āš„)+2 š^ā²ā² š+šš^ā²=šš^š+šš^(āš)+š Now, we know that š„š¦=šš^š„+š š^(āš„)+š„^2 š„š¦āš„^2=šš^š„+š š^(āš„) šš^š+š š^(āš)=ššāš^š Putting (2) in (1) š¦^ā²ā² š„+2š¦^ā²=šš^š+šš^(āš)+2 š¦^ā²ā² š„+2š¦^ā²=ššāš^š+2 (š^2 š¦)/(šš„^2 ) š„+2 šš¦/šš„=ššāš^š+2 (š ^š š)/(š š^š ) š+š š š/š šāšš+š^š=š ā“ The given function is a solution