# Misc 2 (iii) - Chapter 9 Class 12 Differential Equations (Term 2)

Last updated at Aug. 20, 2021 by Teachoo

Miscellaneous

Misc 1 (i)

Misc 1 (ii)

Misc 1 (iii) Important

Misc 2 (i)

Misc 2 (ii) Important

Misc 2 (iii) You are here

Misc 2 (iv) Important

Misc 3 Deleted for CBSE Board 2022 Exams

Misc 4 Important

Misc 5 Important Deleted for CBSE Board 2022 Exams

Misc 6

Misc 7 Important

Misc 8

Misc 9 Important

Misc 10 Important

Misc 11

Misc 12 Important

Misc 13

Misc 14 Important

Misc 15 Important

Misc 16 (MCQ)

Misc 17 (MCQ) Important Deleted for CBSE Board 2022 Exams

Misc 18 (MCQ)

Chapter 9 Class 12 Differential Equations (Term 2)

Serial order wise

Last updated at Aug. 20, 2021 by Teachoo

Misc 2 For each of the exercise given below , verify that the given function (ππππππππ‘ ππ ππ₯ππππππ‘) is a solution of the corresponding differential equation . (iii) π¦=π₯ sinβ‘3π₯ : (π^2 π¦)/(ππ₯^2 )+9π¦β6 cosβ‘γ3π₯=0γ π¦=π₯ sinβ‘3π₯ Differentiating w.r.t x π¦^β²=(π₯ π ππβ‘3π₯ )^β² π¦^β²=π₯^β² sinβ‘3π₯+π₯(sinβ‘3π₯)β² π¦^β²=sinβ‘3π₯+π₯Γ3 cosβ‘3π₯ π¦^β²=sinβ‘3π₯+3π₯ cosβ‘3π₯ Differentiating again w.r.t. x π¦^β²β²=(sinβ‘3π₯ )^β²+(3π₯ cosβ‘3π₯ )^β² π¦^β²β²=3 cosβ‘3π₯+γ3(π₯)γ^β² cosβ‘3π₯+3π₯ (cosβ‘3π₯ )^β² π¦^β²β²=3 cosβ‘3π₯+3 cosβ‘3π₯+3π₯(β3 sinβ‘3π₯) π¦^β²β²=6 cosβ‘3π₯β9π₯ sinβ‘3π₯ Putting π¦=π₯ sinβ‘3π₯ π¦^β²β²=6 cosβ‘3π₯β9π¦ π¦^β²β²+9π¦β6 cosβ‘3π₯=0 Thus, Given Function is a solution of the Differential Equation