Misc 6 Find the general solution of the differential equation + 1 2 1 2 =0 + 1 2 1 2 = 0 = 1 + 2 1 + 2 1 2 = 1 2 Integrating both sides 1 2 = 1 2 sin 1 y = sin 1 x + C sin 1x + sin 1 y = C

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.

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