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Miscellaneous
Last updated at April 16, 2024 by Teachoo
Misc 4 Find the general solution of the differential equation ππ¦/ππ₯+β((1βπ¦^2)/(1βπ₯^2 ))=0ππ¦/ππ₯+β((1 β π¦^2)/(1 β π₯^2 )) = 0 ππ¦/ππ₯ = β β((1 + π¦^2)/(1 + π₯^2 )) π π/β(π β π^π )=π π/β(π β π^π ) Integrating both sides β«1βππ¦/β(1 β π¦^2 ) = β«1βππ₯/β(1 β π₯^2 ) sinβ1 y = β sinβ1 x + C sinβ1x + sinβ1 y = C