
Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Miscellaneous
Misc 1 (ii)
Misc 1 (iii) Important
Misc 2 (i)
Misc 2 (ii) Important
Misc 2 (iii)
Misc 2 (iv) Important
Misc 3 Important
Misc 4
Misc 5 Important
Misc 6
Misc 7 Important
Misc 8 Important
Misc 9
Misc 10 Important
Misc 11
Misc 12 Important
Misc 13 (MCQ)
Misc 14 (MCQ) Important You are here
Misc 15 (MCQ)
Question 1 Deleted for CBSE Board 2024 Exams
Question 2 Important Deleted for CBSE Board 2024 Exams
Question 3 Important Deleted for CBSE Board 2024 Exams
Last updated at May 29, 2023 by Teachoo
Misc 17 The general solution of a differential equation of the type ππ₯/ππ¦+P1π₯=π1 is (A) π¦ π^β«1βγP1 ππ¦γ=β«1βγ(π1π^β«1βγP1 ππ¦γ )ππ¦+πΆγ (B) π¦. π^β«1βγP1 ππ₯γ=β«1βγ(π1π^β«1βγP1 ππ₯γ )ππ₯+πΆγ (C) π₯ π^β«1βγP1 ππ¦γ=β«1βγ(π1π^β«1βγP1 ππ¦γ )ππ¦+πΆγ (D) π₯ π^β«1βγP1 ππ₯γ=β«1βγ(π1π^β«1βγP1 ππ₯γ )ππ₯+πΆγ Differential equation is of type ππ₯/ππ¦+P1π₯=π1 where P1 & Q1 are functions of y IF = π^β«1βγP1 ππ¦γ General solution is x (IF) = β«1βγ(π_1ΓπΌπΉ) ππ¦+πγ π₯ π^β«1βγP1 ππ¦γ=β«1βγ(π1π^β«1βγP1 ππ¦γ ) ππ¦+πΆγ β΄ Option (C) is the correct answer.