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Miscellaneous
Last updated at April 16, 2024 by Teachoo
Misc 14 The general solution of a differential equation of the type ππ₯/ππ¦+P1π₯=π1 is (A) π¦ π^β«1βγP1 ππ¦γ=β«1βγ(π1π^β«1βγP1 ππ¦γ )ππ¦+πΆγ (B) π¦. π^β«1βγP1 ππ₯γ=β«1βγ(π1π^β«1βγP1 ππ₯γ )ππ₯+πΆγ (C) π₯ π^β«1βγP1 ππ¦γ=β«1βγ(π1π^β«1βγP1 ππ¦γ )ππ¦+πΆγ (D) π₯ π^β«1βγP1 ππ₯γ=β«1βγ(π1π^β«1βγP1 ππ₯γ )ππ₯+πΆγDifferential equation is of type ππ₯/ππ¦+P1π₯=π1 where P1 & Q1 are functions of y IF = π^β«1βγππ π πγ General solution is x (IF) = β«1βγ(π_1ΓπΌπΉ) ππ¦+πγ π π^β«1βγππ π πγ=β«1βγ(πΈππ^β«1βγππ π πγ ) π π+πͺγ So, the correct answer is (c)