Misc 17 (MCQ) - Chapter 9 Class 12 Differential Equations (Term 2)
Last updated at Aug. 11, 2021 by Teachoo
Miscellaneous
Misc 1 (i)
Misc 1 (ii)
Misc 1 (iii) Important
Misc 2 (i)
Misc 2 (ii) Important
Misc 2 (iii)
Misc 2 (iv) Important
Misc 3 Deleted for CBSE Board 2022 Exams
Misc 4 Important
Misc 5 Important Deleted for CBSE Board 2022 Exams
Misc 6
Misc 7 Important
Misc 8
Misc 9 Important
Misc 10 Important
Misc 11
Misc 12 Important
Misc 13
Misc 14 Important
Misc 15 Important
Misc 16 (MCQ)
Misc 17 (MCQ) Important Deleted for CBSE Board 2022 Exams You are here
Misc 18 (MCQ)
Chapter 9 Class 12 Differential Equations (Term 2)
Serial order wise
Transcript
Misc 17 The general solution of a differential equation of the type ππ₯/ππ¦+P1π₯=π1 is (A) π¦ π^β«1βγP1 ππ¦γ=β«1βγ(π1π^β«1βγP1 ππ¦γ )ππ¦+πΆγ (B) π¦. π^β«1βγP1 ππ₯γ=β«1βγ(π1π^β«1βγP1 ππ₯γ )ππ₯+πΆγ (C) π₯ π^β«1βγP1 ππ¦γ=β«1βγ(π1π^β«1βγP1 ππ¦γ )ππ¦+πΆγ (D) π₯ π^β«1βγP1 ππ₯γ=β«1βγ(π1π^β«1βγP1 ππ₯γ )ππ₯+πΆγ Differential equation is of type ππ₯/ππ¦+P1π₯=π1 where P1 & Q1 are functions of y IF = π^β«1βγP1 ππ¦γ General solution is x (IF) = β«1βγ(π_1ΓπΌπΉ) ππ¦+πγ π₯ π^β«1βγP1 ππ¦γ=β«1βγ(π1π^β«1βγP1 ππ¦γ ) ππ¦+πΆγ β΄ Option (C) is the correct answer.
