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Misc 16 - Chapter 9 Class 12 Differential Equations
Last updated at Nov. 13, 2019 by Teachoo
Transcript
Misc 16 The general solution of the differential equation (π¦ ππ₯βπ₯ ππ¦)/π¦=0 is (A) π₯π¦=πΆ (B) π₯=πΆπ¦^2 (C) π¦=πΆπ₯ (D) π¦=πΆπ₯^2 (π¦ ππ₯ β π₯ ππ¦)/π¦=0 ( π¦ ππ₯)/π¦β ( π₯ ππ¦)/π¦=0 dx = (π₯ ππ₯)/π¦ ππ₯/π₯ = ππ¦/π¦ Integrating both sides. β«1βγ(ππ₯ )/π₯=(ππ¦ )/(π¦ )γ log x = log y + log c1 log x β log y = log c1 log ((π₯ )/π¦) = log c1 (π₯ )/π¦ = c1 y = π₯/π_1 y = cx β΄ Option (C) is the correct answer
Chapter 9 Class 12 Differential Equations
Serial order wise
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.