
Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Miscellaneous
Misc 1 (ii)
Misc 1 (iii) Important
Misc 2 (i)
Misc 2 (ii) Important
Misc 2 (iii)
Misc 2 (iv) Important
Misc 3 Important
Misc 4
Misc 5 Important
Misc 6
Misc 7 Important
Misc 8 Important
Misc 9
Misc 10 Important
Misc 11
Misc 12 Important
Misc 13 (MCQ) You are here
Misc 14 (MCQ) Important
Misc 15 (MCQ)
Question 1 Deleted for CBSE Board 2024 Exams
Question 2 Important Deleted for CBSE Board 2024 Exams
Question 3 Important Deleted for CBSE Board 2024 Exams
Last updated at May 29, 2023 by Teachoo
Misc 16 The general solution of the differential equation (π¦ ππ₯βπ₯ ππ¦)/π¦=0 is (A) π₯π¦=πΆ (B) π₯=πΆπ¦^2 (C) π¦=πΆπ₯ (D) π¦=πΆπ₯^2 (π¦ ππ₯ β π₯ ππ¦)/π¦=0 ( π¦ ππ₯)/π¦β ( π₯ ππ¦)/π¦=0 dx = (π₯ ππ₯)/π¦ ππ₯/π₯ = ππ¦/π¦ Integrating both sides. β«1βγ(ππ₯ )/π₯=(ππ¦ )/(π¦ )γ log x = log y + log c1 log x β log y = log c1 log ((π₯ )/π¦) = log c1 (π₯ )/π¦ = c1 y = π₯/π_1 y = cx β΄ Option (C) is the correct answer