Question 1 - Area of Triangles - Areas of Parallelograms and Triangles

Last updated at Dec. 16, 2024 by

Ex 9.3, 1 - In fig, E is any point on median AD of - Ex 9.3

Ex 9.3, 1 - Chapter 9 Class 9 Areas of Parallelograms and Triangles - Part 2

Share on WhatsApp

Transcript

Question 1 In Fig, E is any point on median AD of a ABC. Show that ar (ABE) = ar (ACE). Given : ABC is a triangle with AD as medium i.e. BD = CD E is any point on AD. To Prove : ar ( ABE) = ar ( ACE) Proof: Join EB and EC Subtracting (1) and (2) ar ( ABD) ar ( EBD) = ar ( ADC) ar ( EDC) ar ( ABE) = ar ( ACE) Hence, Proved

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo