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Ex 9.3, 1 - In fig, E is any point on median AD of - Ex 9.3

Ex 9.3, 1 - Chapter 9 Class 9 Areas of Parallelograms and Triangles - Part 2

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Ex 9.3, 1 In Fig, E is any point on median AD of a ABC. Show that ar (ABE) = ar (ACE). Given : ABC is a triangle with AD as medium i.e. BD = CD E is any point on AD. To Prove : ar ( ABE) = ar ( ACE) Proof: Join EB and EC Subtracting (1) and (2) ar ( ABD) ar ( EBD) = ar ( ADC) ar ( EDC) ar ( ABE) = ar ( ACE) Hence, Proved

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.