1. Chapter 9 Class 9 - Areas of Parallelograms and Triangles (Deleted)
  2. Serial order wise
  3. Ex 9.2

Ex 9.2, 1 - Chapter 9 Class 9 - Areas of Parallelograms and Triangles (Deleted)

Last updated at June 29, 2018 by

1 Ex 9.2, 1 - In given figure, ABCD is parallelogram.jpg

Ex 9.2, 1 - Chapter 9 Class 9 Areas of Parallelograms and Triangles - Part 2

  1. Chapter 9 Class 9 - Areas of Parallelograms and Triangles (Deleted)
  2. Serial order wise

    3. Ex 9.2

    Ex 9.3 →

Transcript

Ex 9.2, 1 In the given figure, ABCD is parallelogram, AE DC and CF AD. If AB = 16 cm, AE = 8 cm and CF = 10 cm, find AD. Area of a parallelogram = Base Altitude From (1) & (2) 16 8 = AD 10 AD = (16 8)/10 cm = 12.8 cm Thus, the length of AD is 12.8 cm.

Chapter 9 Class 9 - Areas of Parallelograms and Triangles (Deleted)
Serial order wise

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.