Ex 9.2, 1 - Class 9
Last updated at May 29, 2018 by Teachoo
Transcript
Ex 9.2, 1 In the given figure, ABCD is parallelogram, AE ⊥ DC and CF ⊥ AD. If AB = 16 cm, AE = 8 cm and CF = 10 cm, find AD. Area of a parallelogram = Base × Altitude From (1) & (2) 16 × 8 = AD × 10 AD = (16 × 8)/10 cm = 12.8 cm Thus, the length of AD is 12.8 cm.
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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.
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How that answer came
Pqrs is a parallelogram the length of s r and p x are 7 cm and 2.5 CM . if the length of PX is 5 cm then what will be RQ
Where is hf
Sir regarding the problem 9th class maths ex-9.2(1) . Considering the diagram the final solution is that AD=12.48 . But while considering only right triangle CDF and solving for DF =√DC^2-CF^2 i get DF = 12.48 . How come it's possible ???
DC=AB
How
