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Ex 9.2, 1 - In given figure, ABCD is parallelogram - Paralleograms with same base & same parallel lines

  1. Chapter 9 Class 9 Areas of parallelograms and Triangles
  2. Serial order wise
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Ex 9.2, 1 In the given figure, ABCD is parallelogram, AE ⊥ DC and CF ⊥ AD. If AB = 16 cm, AE = 8 cm and CF = 10 cm, find AD. Area of a parallelogram = Base × Altitude From (1) & (2) 16 × 8 = AD × 10 AD = (16 × 8)/10 cm = 12.8 cm Thus, the length of AD is 12.8 cm.

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can ask questions here.
  • Maheswara Prathap's image
    Maheswara Prathap
    Oct. 24, 2017, 6:06 a.m.

    Sir regarding the problem 9th class maths  ex-9.2(1) . Considering the diagram the final solution is that AD=12.48 . But while considering only right triangle CDF and solving for DF =√DC^2-CF^2  i get DF = 12.48 . How come it's possible ??? 

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  • ayush namdev's image
  • Ajjad Sigaha's image
    Pqrs is a parallelograms qr is produced to e such that qr is equal to re pe interest sr at f if area of triangle sfq is 3 centimetres square find area of pqrs

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