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Ex 9.2, 5 - In figure, PQRS and ABRS are parallelograms - Paralleograms & triangles with same base & same parallel lines

  1. Chapter 9 Class 9 Areas of parallelograms and Triangles
  2. Serial order wise
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Ex 9.2, 5 In the given figure, PQRS and ABRS are parallelograms and X is any point on side BR. Show that (i) ar (PQRS) = ar (ABRS) Since PQRS is a parallelogram PQ ∥ RS & ABRS is also a parallelogram So, AB ∥ RS Since PQ ∥ RS & AB ∥ RS We can say that PB ∥ RS Now, PQRS & ABRS are two parallelograms with the same base RS and between the same parallels PB & RS ∴ ar (PQRS) = ar (ABRS) Ex 9.2, 5 In the given figure, PQRS and ABRS are parallelograms and X is any point on side BR. Show that (ii) ar (AXS) = 1/2 ar (PQRS) Since ABRS is a parallelogram, AS ∥ BR Δ AXS and parallelogram ABRS lie on the same base AS and are between the same parallel lines AS and BR, ∴ Area (ΔAXS) =  1/2 Area (ABRS) ⇒ Area (ΔAXS) =  1/2 Area (PQRS) Hence proved

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  • Vikash Srivastava's image
    Vikash Srivastava
    Sept. 24, 2017, 6:42 p.m.

    in the triangle abc p is the point on bc such that of triangle abcsuch that bp:pc=1:2 and q is a point on  ap such that pq:qa=2:3 prove that area od triangle aqc: area triangle abc = 2:3

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