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Ex 9.2, 3 - P and Q are any two points lying on sides DC - Paralleograms & triangles with same base & same parallel lines

Ex 9.2, 3 - Chapter 9 Class 9 Areas of Parallelograms and Triangles - Part 2

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Ex 9.2, 3 P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD. Show that ar (APB) = ar (BQC). Given: A parallelogram ABCD where P & Q are any points on DC and AD resp. To prove: ar (APB) = ar (BQC) Proof: ABCD is a parallelogram So, AB CD & AD BC From (1) & (2) Area ( APB) = Area (BQC) Hence proved

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.