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Last updated at May 29, 2018 by Teachoo

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Example 1 In given figure, ABCD is a parallelogram and EFCD is a rectangle. Also, AL ⊥ DC. Prove that (i) ar (ABCD) = ar (EFCD) Given that ABCD is a parallelogram Hence AB ∥ CD We know that a rectangle is also a parallelogram, so EFCD is also a parallelogram So, EF ∥ CD Since AB ∥ CD and EF ∥ CD we can say that EB ∥ CD Now, ABCD & EFDC are two parallelograms with the same base CD and between the same parallels EB & CD ∴ ar (ABCD) = ar (EFCD) Example 1 In Fig., ABCD is a parallelogram and EFCD is a rectangle. Also, AL ⊥ DC. Prove that (ii) ar (ABCD) = DC × AL ABCD is a parallelogram with Base DC and altitude AL Now, Area of a parallelogram = Base × Corresponding altitude ∴ ar (ABCD) = DC × AL Hence proved

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.