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Ex 9.3
Ex 9.3, 2 Important Deleted for CBSE Board 2023 Exams
Ex 9.3, 3 Deleted for CBSE Board 2023 Exams
Ex 9.3, 4 Deleted for CBSE Board 2023 Exams
Ex 9.3, 5 Important Deleted for CBSE Board 2023 Exams
Ex 9.3, 6 Important Deleted for CBSE Board 2023 Exams
Ex 9.3, 7 Important Deleted for CBSE Board 2023 Exams
Ex 9.3, 8 Deleted for CBSE Board 2023 Exams
Ex 9.3, 9 Important Deleted for CBSE Board 2023 Exams
Ex 9.3, 10 Deleted for CBSE Board 2023 Exams
Ex 9.3, 11 Important Deleted for CBSE Board 2023 Exams
Ex 9.3, 12 Important Deleted for CBSE Board 2023 Exams
Ex 9.3, 13 Deleted for CBSE Board 2023 Exams You are here
Ex 9.3, 14 Deleted for CBSE Board 2023 Exams
Ex 9.3, 15 Deleted for CBSE Board 2023 Exams
Ex 9.3, 16 Important Deleted for CBSE Board 2023 Exams
Last updated at March 22, 2023 by Teachoo
Ex 9.3, 13 ABCD is a trapezium with AB ∥ DC . A line parallel to AC intersects AB at X and BC at Y. Prove that ar(ADX) = ar(ACY). Given: A trapezium ABCD where AB ∥ DC & AC ∥ XY To prove: ar (ADX) = ar (ACY) Construction: Joining XC Proof : For ΔACX and ΔACY lie on the same base AC and are between parallel lines AC & XY ∴ ar(ACX) = ar(ACY) Also, for ΔACX and ΔADX lie on the same base AX and are between parallel lines AX & DC ∴ ar(ACX) = ar(ADX) From (1) & (2), ar( ACY ) = ar(ADX) Hence proved