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Ex 9.3, 2 - In triangle ABC, E is mid-point of median AD - Ex 9.3

  1. Chapter 9 Class 9 Areas of parallelograms and Triangles
  2. Serial order wise
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Ex 9.3, 2 In a triangle ABC , E is the mid-point of median AD show that ar(BED) = 1/4 ar (ABC). Given: Δ ABC, with AD as median i.e. BD = CD & E is the mid-point of AD, i.e., AE = DE To prove: ar (BED) = 1/4 ar (ABC). Proof : AD is a median of Δ ABC & median divides a triangle into two triangles of equal area ∴ ar (ABD) = ar (ACD) ⇒ ar (ABD) = 1/2 ar (ABC) In Δ ABD, BE is the median median divides a triangle into two triangles of equal area ∴ ar (BED) = ar (BEA) ⇒ ar (BED) = 1/2 ar (ABD) ⇒ ar (BED) = 1/2× 1/2 ar (ABC) ⇒ ar (BED) = 1/4 ar (ABC) Hence proved

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