Last updated at Aug. 25, 2021 by

Transcript

Ex 9.3, 16 In figure, ar(DRC) = ar(DPC) and ar(BDP) = ar(ARC). Show that both the quadrilaterals ABCD and DCPR are trapeziums. Given: ar(DRC) = ar(DPC) & ar(BDP) = ar(ARC) To prove: ABCD & DCPR are trapeziums Proof: Given ar(DRC) = ar(DPC) So, DPC and DRC lie on the same base DC and are equal in area & They lie between DC & PR Hence DC PR In DCPR, one pair of opposite sides of quadrilateral DCPR are parallel Hence, DCPR is a trapezium . Now, given that ar(BDP) = ar(ARC) & ar(DPC) = ar(DRC) Subtracting(1) & (2),i.e., (1) (2) ar(BDP) ar(DPC) = ar(ARC) ar(DRC) ar(BDC) = ar(ADC) Now, ADC and BDC lie on the same base DC and are equal in area & They lie between lines DC & AB DC AB Since one pair of opposite sides of quadrilateral ABCD are parallel Hence, ABCD is a trapezium .

Ex 9.3

Ex 9.3, 1
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Ex 9.3, 2 Important Deleted for CBSE Board 2022 Exams

Ex 9.3, 3 Deleted for CBSE Board 2022 Exams

Ex 9.3, 4 Deleted for CBSE Board 2022 Exams

Ex 9.3, 5 Important Deleted for CBSE Board 2022 Exams

Ex 9.3, 6 Important Deleted for CBSE Board 2022 Exams

Ex 9.3, 7 Important Deleted for CBSE Board 2022 Exams

Ex 9.3, 8 Deleted for CBSE Board 2022 Exams

Ex 9.3, 9 Important Deleted for CBSE Board 2022 Exams

Ex 9.3, 10 Deleted for CBSE Board 2022 Exams

Ex 9.3, 11 Important Deleted for CBSE Board 2022 Exams

Ex 9.3, 12 Important Deleted for CBSE Board 2022 Exams

Ex 9.3, 13 Deleted for CBSE Board 2022 Exams

Ex 9.3, 14 Deleted for CBSE Board 2022 Exams

Ex 9.3, 15 Deleted for CBSE Board 2022 Exams

Ex 9.3, 16 Important Deleted for CBSE Board 2022 Exams You are here

Chapter 9 Class 9 - Areas of Parallelograms and Triangles (Deleted)

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.