Ex 9.3, 14
Last updated at Dec. 8, 2016 by Teachoo
Transcript
Ex 9.3, 14 In figure, AP ∥ BQ ∥ CR. Prove that ar(AQC) = ar(PBR). Given: AP ∥ BQ ∥ CR To prove: ar(AQC) = ar(PBR) Proof: Since ΔABQ and ΔPBQ lie on the same base BQ and are between parallel lines BQ & AP ∴ ar(ABQ) = ar(PBQ) Also, ΔCBQ and ΔRBQ lie on the same base BQ and are between parallel lines BQ & CR ∴ ar(CBQ) = ar(RBQ) Adding (1) & (2) ar(AQB) + ar(BQC) = ar(PBQ) + ar(QBR) ⇒ ar(AQC) = ar(PBR). Hence proved
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CA Maninder Singh
CA Maninder Singh is a Chartered Accountant for the past 8 years. He provides courses for Practical Accounts, Taxation and Efiling at teachoo.com .