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Ex 9.3, 14 - In figure, AP || BQ || CR. Prove ar(AQC) - Triangles with same base & same parallel lines

Ex 9.3, 14 - Chapter 9 Class 9 Areas of Parallelograms and Triangles - Part 2

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Ex 9.3, 14 In figure, AP BQ CR. Prove that ar(AQC) = ar(PBR). Given: AP BQ CR To prove: ar(AQC) = ar(PBR) Proof: Since ABQ and PBQ lie on the same base BQ and are between parallel lines BQ & AP ar(ABQ) = ar(PBQ) Also, CBQ and RBQ lie on the same base BQ and are between parallel lines BQ & CR ar(CBQ) = ar(RBQ) Adding (1) & (2) ar(AQB) + ar(BQC) = ar(PBQ) + ar(QBR) ar(AQC) = ar(PBR). Hence proved

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.