


Ex 9.3
Ex 9.3, 2 Important Deleted for CBSE Board 2022 Exams
Ex 9.3, 3 Deleted for CBSE Board 2022 Exams
Ex 9.3, 4 Deleted for CBSE Board 2022 Exams
Ex 9.3, 5 Important Deleted for CBSE Board 2022 Exams
Ex 9.3, 6 Important Deleted for CBSE Board 2022 Exams
Ex 9.3, 7 Important Deleted for CBSE Board 2022 Exams
Ex 9.3, 8 Deleted for CBSE Board 2022 Exams
Ex 9.3, 9 Important Deleted for CBSE Board 2022 Exams
Ex 9.3, 10 Deleted for CBSE Board 2022 Exams
Ex 9.3, 11 Important Deleted for CBSE Board 2022 Exams You are here
Ex 9.3, 12 Important Deleted for CBSE Board 2022 Exams
Ex 9.3, 13 Deleted for CBSE Board 2022 Exams
Ex 9.3, 14 Deleted for CBSE Board 2022 Exams
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Ex 9.3, 16 Important Deleted for CBSE Board 2022 Exams
Last updated at March 2, 2017 by Teachoo
Ex 9.3, 11 In the given figure, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that (i) ar (ACB) = ar (ACF) Given: A pentagon ABCDE where BF AC To prove: ar (ACB) = ar (ACF) Proof : ACB and ACF lie on the same base AC and are between the same parallels AC and BF. ar( ACB) = ar( ACF) Ex 9.3, 11 In the given figure, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that (ii) ar (AEDF) = ar (ABCDE) In part(i), we proved that ar( ACB) = ar( ACF) Adding ar(AEDC) both sides ar( ACB) + ar(AEDC) = ar( ACF) + ar(AEDC) Area (ABCDE) = Area (AEDF) Hence proved