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Last updated at March 2, 2017 by Teachoo
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Ex 9.3, 11 In the given figure, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that (i) ar (ACB) = ar (ACF) Given: A pentagon ABCDE where BF AC To prove: ar (ACB) = ar (ACF) Proof : ACB and ACF lie on the same base AC and are between the same parallels AC and BF. ar( ACB) = ar( ACF) Ex 9.3, 11 In the given figure, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that (ii) ar (AEDF) = ar (ABCDE) In part(i), we proved that ar( ACB) = ar( ACF) Adding ar(AEDC) both sides ar( ACB) + ar(AEDC) = ar( ACF) + ar(AEDC) Area (ABCDE) = Area (AEDF) Hence proved
Ex 9.3
Ex 9.3, 2 Important Not in Syllabus - CBSE Exams 2021
Ex 9.3, 3 Not in Syllabus - CBSE Exams 2021
Ex 9.3, 4 Not in Syllabus - CBSE Exams 2021
Ex 9.3, 5 Not in Syllabus - CBSE Exams 2021
Ex 9.3, 6 Not in Syllabus - CBSE Exams 2021
Ex 9.3, 7 Important Not in Syllabus - CBSE Exams 2021
Ex 9.3, 8 Not in Syllabus - CBSE Exams 2021
Ex 9.3, 9 Not in Syllabus - CBSE Exams 2021
Ex 9.3, 10 Not in Syllabus - CBSE Exams 2021
Ex 9.3, 11 Important Not in Syllabus - CBSE Exams 2021 You are here
Ex 9.3, 12 Not in Syllabus - CBSE Exams 2021
Ex 9.3, 13 Not in Syllabus - CBSE Exams 2021
Ex 9.3, 14 Not in Syllabus - CBSE Exams 2021
Ex 9.3, 15 Not in Syllabus - CBSE Exams 2021
Ex 9.3, 16 Not in Syllabus - CBSE Exams 2021
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